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dem82 [27]
2 years ago
14

A yard cleanup service charges a $345 fee plus $16.25 per hour. Another cleanup service charges a $213 fee plus $24.50 per hour.

How long is a job for which the two companies' costs are the same?
Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
4 0

The time for the job for which the two company are the same is 16

<h3>How to form the equation and find the cost?</h3>

A yard cleanup service charges a $345 fee plus $16.25 per hour. Therefore,

using linear equation,

y = mx + c

where

  • y = total cost
  • x = time

Therefore,

y = 345 + 16.25x

Another cleanup service charges a $213 fee plus $24.50 per hour. Therefore,

y = 213 + 24.50x

Hence, the time when both cost are the same is as follows;

213 + 24.50x =  345 + 16.25x

213 - 345 = 16.25x - 24.50x

-132 = -8.25x

x = 132 / 8.25

x = 16

learn more on equation here: brainly.com/question/2072580

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