Deanna uses only fruit juice and sparkling water to make
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Using probability of independent events, it is found that there is a:
- 0.3066 = 30.66% probability that both teams win their games.
- 0.1983 = 19.83% probability that neither favored team wins its game.
- 0.8017 = 80.17% probability that at least one of the favored teams wins its games.
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- If two events, A and B, are independent, the <u>probability of both happening is the multiplication of the probabilities of each happening</u>, that is:
One team is favored in its semi-final match by odds of 1.40 to 1.60:
Thus it's probability of winning is:
Another squad is favored in its contest by odds of 2.30 to 1.70:
Thus it's probability of winning is:
The probability of both winning is:
0.3066 = 30.66% probability that both teams win their games.
The probability of neither winning is:
0.1983 = 19.83% probability that neither favored team wins its game.
At least one is <u>complementary to neither</u>, thus, the probability of at least one is:
0.8017 = 80.17% probability that at least one of the favored teams wins its games.
A similar problem is given at brainly.com/question/24935451