This is the correct way to solve the problem :
You add 3 and 8 together.
you see if it equals -2 or not.
I hope this helps!
It is 19. Hope this helps!!
Volume of the pyramid:

Perimeter of the cross-section:


Area of the cross-section:


First derivative test:

Then the height of the cross-section/pyramid is

The volume of the pyramid that maximizes the cross-sectional area
is

Answer:
0,-2,-4
Step-by-step explanation:
Answer:
Step-by-step explanation:
0.178