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pogonyaev
2 years ago
13

A 4. 0 nc positive point charge is located at point a in the figure. (figure 1) what is the electric potential at point b?.

Physics
1 answer:
algol [13]2 years ago
7 0

The electric potential at point b experienced by the charge cab be determined using the formulas given.

<h3>Electric potential</h3>

The electric potential of a point charge is the work done in moving the charge from infinity to certain point against the electric field.

V = Ed

V = (F/q)d

V = (Fd)/q

where;

  • V is the electric potential
  • F is electric force
  • E is the electric field
  • q is the charge

Thus, the electric potential at point b experienced by the charge cab be determined using the formulas given.

Learn more about electric potential here: brainly.com/question/14306881

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How much work is needed to stop a 1,110 kg car that is moving straight down the
schepotkina [342]

Answer:

382.74 kJ.

Explanation:

The work that must be done to stop an 1100 kg car travelling at 59  km/h is  - 382.74 kJ.

3 0
3 years ago
To balance a chemical equation we use______. <br> -coefficients <br> -subscripts
Vitek1552 [10]

Answer:

Coefficients

Explanation:

  • Coefficients are used to balance chemical equations.
  • According to the law of conservation of mass, the mass of the reactants in a chemical equation should be equivalent to the mass of the products.
  • The conservation of mass is achieved in chemical equations is achieved through balancing chemical equations.
  • <em><u>Balancing chemical equations is a try and error of putting appropriate coefficients to the reactants or products to ensure that the number of atoms of each element are equal on the side of the reactants and that of products. </u></em>
3 0
3 years ago
A speed skater is sliding across the ice at a speed of 19 m/s when she encounters a rough patch of ice that is 2.0 m wide. As sh
Stells [14]

Answer:

-9.25 m/s^2

Explanation:

The motion of the skater is a uniformly accelerated motion, so we can find the deceleration by using the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

In this problem, we have:

u = 19 m/s is the initial velocity of the skater

v = 18 m/s is the final velocity of the skater

s = 2.0 m is the displacement

Solving for a, we can find the acceleration:

a=\frac{v^2-u^2}{2s}=\frac{18^2-19^2}{2(2.0)}=-9.25 m/s^2

And the negative sign tells us that the acceleration is in the opposite direction to the motion (so, it is a deceleration)

5 0
4 years ago
A dog exerts a force of 30N to move a wagon 2m in 5s. What is the power of the dog
Hunter-Best [27]

Explanation:

power=f×v. recall= distances/ time

= f× d/t

= 30 × 2/5

=12watt

6 0
3 years ago
A 50 mL graduated cylinder contains 25.0 mL of water. A 42.5040 g piece of gold is placed in the graduated cylinder and the wate
Elenna [48]

Answer:

19320 kg/m³

Explanation:

density: This can be defined as the ratio of the mass of a body to its volume. The S.I unit of Density is kg/m³.

The formula of density is given as,

D = m/v ......................... Equation 1.

Where D = Density of the gold, m = mass of the gold, v = volume of the gold.

Note: From Archimedes's Principle, the piece of gold displace an amount of water that is equal to it's volume.

Amount of water displace = 27.2 - 25 = 2.2 mL.

Given: m = 42.504 g = 0.042504 kg, v = 2.2 mL = (2.2/10⁶) m³ = 0.0000022 m³

Substitute into equation 1

D = 0.042504/0.0000022

D = 19320 kg/m³

Hence the density of the piece of gold = 19320 kg/m³

5 0
3 years ago
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