Question: calculate their densties in Si unit.
200mg,0.0004m³
Answer:
0.5 kg/m³
Explanation:
Applying,
D = m/V........................ Equation 1
Where D = density, m = mass, V = volume.
From the question,
Given: m = 200 mg = (200/1000000) kg = 2.0×10⁻⁴ kg, V = 0.0004 m³ = 4.0×10⁻⁴ m³
Substitute these values into equation 1
D = (2.0×10⁻⁴ kg)/(4.0×10⁻⁴)
D = 2/4
D = 0.5 kg/m³
Hence the density in S.I unit is 0.5 kg/m³
The momentum of an object is given by:
p = mv
m is the object's mass and v is its velocity.
Given values:
m = 15kg
v = 25m/s
Plug in the values and solve for p:
p = 15*25
p = 375kg×m/s
Answer:
a) 6.8 Volt
b) 1.21Цm
Explanation:
We are given from the question that
The zero -bias depletion layer width(
) is 0.4Цm
The built in voltage φj is 0.85V
Now to calculate the reverse voltage(
) that would be required to triple the depletion - layer width.
The depletion - layer width (
) of the diode has the formula

For three times of
we have

=> 
=> 
Substituting value of φj
We have

= 6.8 V
The required bias voltage
is 6.8 V
The solution for the b part of the question is uploaded on first image
Centripetal force = (mv^2)/r
so r = (mv^2)/ force = 246500 / 1100 = 224 m