Aswer:
False, the values of the distance traveled and the displacement only coincide when the trayectorie is a straight line. Otherwise, the distance will always be greater than the offset.
Although these terms are used synonymously in other cases, they are totally different. Since the distance that a mobile travels is the equivalent of the length of its trajectory. Whereas, the displacement will be a vector magnitude.
<u>xXCherryCakeXx</u>.
Explanation:
It is given that,
The Displacement x of particle moving in one dimension under the action of constant force is related to the time by equation as:

Where,
x is in meters and t is in sec
We know that,
Velocity,

(a) i. t = 2 s

At t = 4 s

(b) Acceleration,

Pu t = 3 s in above equation
So,

Hence, (a) (i) v = 55 m/s (ii) v = 211 m/s and (b) 78 m/s²
A. Layer C is the right answer out of all the choices
Answer:
B - spring scale and meterstick
Explanation:
The work done by the force of gravity as the object falls is equal to the potential energy of the object.
We know that the gravitational potential energy(PE) of an object is obtained by;
PE =mgΔh
Where;
m = mass of the object
g = acceleration due to gravity
h= height of the object
The spring scale is needed to measure the mass of the object while the meterstick measures the Δh in meters.