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djyliett [7]
3 years ago
13

4. Provide an example of an isolated energy system and explain how it could be changed to create an open energy system. You may

use the examples provided in the lesson or another example.
Physics
2 answers:
levacccp [35]3 years ago
5 0

Answer:

Explanation:

Isolated energy system does not allow the energy or matter transfer, whereas, Open energy system allows energy and matter to exchange. For example, Insulated container (Thermos bottle), if the insulated bottle is filled with hot tea and the container is closed then there will be no exchange of matter and energy but as we open up the top of container then the heat will escape to the surrounding and exchange of matter and energy will take place.

GarryVolchara [31]3 years ago
4 0
<span>Easy, take the top off your Thermos bottle filled with hot coffee. Assuming perfect insulation, that hot coffee is isolated from the environment; but when the top is opened the heat can now escape to that environment.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
</span>
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No the mold should not be of the same size as that of sculpture because the material from which molds is made may shrink or expand depending upon its properties .

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We need to make mold bigger in general so that if there is a need of finishing it can be done easily without altering the size of sculpture.

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What are 3 artificial and 2 natural sources of electromagnetic radiation?
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A student is observing a pendulum swinging back and forth. Each time it swings, the pendulum bob reaches a lower maximum, and ev
vodomira [7]

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the pendulum loses momentum and stops because of gravity and wind resistance. it does not violate the law of conservation of energy because it is not gaining any more momentum than what it had started with

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2 years ago
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A player kicks a football from ground level with an initial velocity of 27.0 30.0 above the horizontal Find the ball's maximum h
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Given

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5 0
2 years ago
A spaceship ferrying workers to Moon Base I takes a straight-line path from the earth to the moon, a distance of 384,000 km. Sup
Tema [17]

Answer:

a) v = 19,149.6 m/s

b) f = 95%

c) t = 346.5min

Explanation:

First put all values in metric units:

15.8 min*\frac{60s}{1min}=948s

The equation of motion you need is:

v_f = a*t+v_0

where v_f is the final velocity, a is acceleration and t is time in hours.

Since the spaceship starts from 0 velocity:

v_f = a*t = 20.2*948 = 19,149.6 m/s

Next, you need to calculate the distances traveled on each interval, considering that both starting and final intervals travel the same distance because the acceleration and time are equal. For this part you need the next motion equation:

x=\frac{v_0+v_f}{2}t

solving for first and last interval:

Since the spaceship starts and finish with 0 velocity:

x=\frac{v}{2}t=\frac{19,149.6}{2}948=9,076,910.4m=9,076.9104km

Then the ship traveled 384,000-9,076.9104*2 = 361,846.1792km at constant speed, which means that it traveled:

f_{constant_speed} =\frac{ x_{constant_speed}}{x_total} =\frac{361,846.1792}{380,000} =0.95

Which in percentage is 95% of the trip.

to calculate total time you need to calculate the time used during constant speed:

t = \frac{361,846,179.2}{19,149.6} = 18,895.75s = 314min

That added to the other interval times:

t_{total} = t_1+t_2+t_3=15.8+314.93+15.8=346.5min

5 0
2 years ago
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