Answer:
2.65m/s
Explanation:
Using the equation of motion:
v² = u²+2a∆S where
v is the final velocity
u is the initial velocity
∆S is the change in distance
a is the acceleration
Given
u = 0m/s
a = 9.8m/s²
∆S = 1.3-0.943
∆S = 0.357m
Substituting the given parameters into the formula
v² = 0²+2(9.8)(0.357)
v² = 0+6.9972
v² = 6.9972
v=√6.9972
v = 2.65m/s
Hence the velocity at which it hit the ground is 2.65m/s
Answer:
The event horizon of a black hole can be thought of either as the place around the black hole where the speed you need to escape becomes greater than the speed of light or as the place where the warping of spacetime around a collapsed star becomes so great that all straight lines pointing outward actually become curved paths bringing you back in. Only black holes have event horizons, so our Sun, which is a star in happy main-sequence equilibrium, cannot have one.
The process of splitting a vector into its components is known as resolution of vectors . It is the reverse process of addition of vectors.In resolution of a vector, a single vector along with its direction is converted into two or more components.
Answer:
The value is ![P = 29400 \ Pa](https://tex.z-dn.net/?f=P%20%3D%2029400%20%5C%20Pa)
Explanation
From the question we are told that
The width of the pool is ![w = 9.0 \ m](https://tex.z-dn.net/?f=w%20%3D%209.0%20%5C%20%20m)
The length is ![l = 24.0 \ m](https://tex.z-dn.net/?f=l%20%3D%20%2024.0%20%5C%20%20m)
The depth is ![d = 3.0 \ m](https://tex.z-dn.net/?f=d%20%3D%20%203.0%20%20%5C%20%20m)
Generally the pressure is mathematically represented as
![P = \rho * g * d](https://tex.z-dn.net/?f=P%20%3D%20%20%5Crho%20%2A%20%20g%20%2A%20d)
here
the density of water
=> ![P = 1000 * 9.8 * 3](https://tex.z-dn.net/?f=P%20%3D%20%201000%20%2A%20%209.8%20%2A%203)
=> ![P = 29400 \ Pa](https://tex.z-dn.net/?f=P%20%3D%2029400%20%5C%20Pa)
Answer:
Pascal
Explanation:
The standard SI unit for pressure measurement is the Pascal (Pa) which is equivalent to one Newton per square meter (N/m2) or the KiloPascal (kPa) where 1 kPa = 1000 Pa.