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Yuliya22 [10]
3 years ago
11

A 60 kg person sits in a chair. How much does the earth pull on the person? (Acceleration due to gravity is -10m/s2) F = mxa → F

= (60kg) x (-10m/s2) → F= -600N or 600N in the downward direction
Physics
1 answer:
MA_775_DIABLO [31]3 years ago
7 0

Answer:

<em>600N(downwards)</em>

Explanations

<em>600N(downwards)</em>

Mas of the person = 60kg

Acceleration due to gravity = -10m/s²

To get the earths pull on the person, we will use the Newton second law of motion;

Force = mass * acceleration;

Force = 60 * -10

Force- -600N

<em>Hence the earth gravitational pull on the person is 600N(downwards). It is downwards due to the negative sign.</em>

<em></em>

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a seismic wave has a measured wavelength of 0.50 km. its frequency is 27 hz. what is the velocity of the wave?
nydimaria [60]

Answer:V=13500m/s

As

V=fλ

Where v is velocity, f is frequency and λ is the wavelength

f=27hz or 27/s

λ=0.50km=0.50*1000m=500m

Putting given values in the formula

V=(27/s)*(500m)

V=13500m/sss

8 0
2 years ago
A bumblebee has a charge of 1.0 µC is placed 10.0 cm from a charge of 2.5 µC. What is the magnitude of the electric force?
allochka39001 [22]

Answer:

F = 2.25 N

Explanation:

Given that,

Charge 1, q_1=1\ \mu C = 10^{-6}\ C

Charge 2, q_2=2.5\ \mu C=2.5\times 10^{-6}\ C

Distance between charges, d = 10 cm = 0.1 m

We need to find the electric force between charges. The formula that is used to find the electric force is given by

F=\dfrac{kq_1q_2}{d^2}\\\\F=\dfrac{9\times 10^9\times 10^{-6}\times 2.5\times 10^{-6}}{(0.1)^2}\\\\=2.25\ N

Hence, the force between charges is 2.25 N.

6 0
3 years ago
Salmon often jump waterfalls to reach their
erik [133]

Answer:

6.35 m/s

Explanation:

The motion of the salmon is equivalent to that of a projectile, which consists of two independent motions:

- A horizontal motion with constant speed

- A vertical motion with constant acceleration (g=-9.8 m/s^2, acceleration of gravity)

The horizontal velocity of the salmon is given by:

v_x = u cos \theta

where

u = ? is the initial speed

\theta=32^{\circ} is the angle of projection

Then the horizontal distance covered by the salmon after a time t is given by

d=v_x t =(u cos \theta) t

Or equivalently, the time taken to cover a distance d is

t=\frac{d}{u cos \theta} (1)

Along the vertical direction, the equation of motion is

h = (u sin \theta) t + \frac{1}{2}gt^2 (2)

where

u sin \theta is the initial vertical velocity

If we substitute (1) into (2), we get:

h = (u sin \theta) \frac{d}{cos \theta} + \frac{1}{2}g(\frac{d}{ ucos \theta})^2=d tan \theta + \frac{gd^2}{2u^2 cos^2 \theta}

We now that in order to reach the breeding grounds, the salmon must travel a distance of

d = 2.02 m

reaching a height of

h = 0.574 m

Substituting these data into the equation and solving for u, we find the initial speed that the salmon must have:

u =\sqrt{ \frac{gd^2}{2(h-d tan \theta) cos^2 \theta}}=\sqrt{\frac{(-9.8)(2.02)^2}{2(0.574-(2.02)(tan 32))(cos^2(32))}}=6.35 m/s

8 0
3 years ago
1. a) What is the weight of a 20.0 kg girl on earth?
ki77a [65]

Answer: weight= 196

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8 0
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Alexandra [31]

Answer:

\huge\color{green}\boxed{\colorbox{red}{Don't know}}

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