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Yuliya22 [10]
2 years ago
11

A 60 kg person sits in a chair. How much does the earth pull on the person? (Acceleration due to gravity is -10m/s2) F = mxa → F

= (60kg) x (-10m/s2) → F= -600N or 600N in the downward direction
Physics
1 answer:
MA_775_DIABLO [31]2 years ago
7 0

Answer:

<em>600N(downwards)</em>

Explanations

<em>600N(downwards)</em>

Mas of the person = 60kg

Acceleration due to gravity = -10m/s²

To get the earths pull on the person, we will use the Newton second law of motion;

Force = mass * acceleration;

Force = 60 * -10

Force- -600N

<em>Hence the earth gravitational pull on the person is 600N(downwards). It is downwards due to the negative sign.</em>

<em></em>

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If a 3 kg block rests on a rough horizontal table and experienced a 2 N force of static friction then what is the coefficient of
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The coefficient of static friction of the block is 0.068.

<h3 />

<h3>What is static friction?</h3>

This is the force between two bodies in contact and tends to oppose their motion. It is also the force that keeps two bodies at rest

To calculate the coefficient of static friction, we use the formula below.

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  • g = acceleration due to gravity
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Make μ the subject of the equation

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Learn more about static friction here: brainly.com/question/13680415

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