Answer:
<h2>
f₀ = 158.12 Hertz</h2>
Explanation:
The fundamental frequency of the string f₀ is expressed as f₀ = V/4L where V is the speed experienced by the string.
where T is the tension in the string and 
is the density of the string
Given T = 600N and = 0.015 g/cm = 0.0015kg/m
The next is to get the length L of the string. Since the string is stretched and fixed at both ends, 200 cm apart, then the length of the string in metres is 2m.
L = 2m
Substituting the derived values into the formula f₀ = V/2L
f₀ = 632.46/2(2)
f₀ = 632.46/4
f₀ = 158.12 Hertz
Hence the fundamental frequency of the string is 158.12 Hertz
Explanation:
Distance = (intial speed)X(Time) + 1/2(acceleration)X(Time) [Third equation of motion]
As initial speed is zero, therefore;
Distance = 1/2(acceleration)X(Time)
= 1/2 (6 X 15)
= 1/2 (90)
= 45 meters
Hence, the object traveled 45 meters.
Answer:
False
Explanation:
The magnitude of any vector is given by,
The magnitude of anything is never negative. It can be even seen from the formula that the components are squared. A squared value can never be negative. Even if the component is negative the square will be always positive.
So, magnitude of the vector is <u>not</u> negative.
Answer:
3. Madison, WI
4. Quito, Equador
6. Main Sequence stars are becoming red giants
Explanation:
