Answer:
Explanation:
The question relates to motion on a circular path .
Let the radius of the circular path be R .
The centripetal force for circular motion is provided by frictional force
frictional force is equal to μmg , where μ is coefficient of friction and mg is weight
Equating cenrtipetal force and frictionl force in the case of car A
mv² / R = μmg
R = v² /μg
= 26.8 x 26.8 / .335 x 9.8
= 218.77 m
In case of moton of car B
mv² / R = μmg
v² = μRg
= .683 x 218.77x 9.8
= 1464.35
v = 38.26 m /s .
Answer:
a) The 99% confidence interval for the mean noise level = [122.44, 151.96]
b) Sample standard deviation, s = 17.3dB
Explanation:
Noise levels at 5 airports = 147,123,119,161,136
Mean noise level
Variance of noise level
Standard deviation,
a) Confidence interval is given by
For 99% confidence interval Z = 2.576,
Number of noises, n = 5
Substituting
The 99% confidence interval for the mean noise level = [122.44, 151.96]
b) Sample standard deviation
Sample standard deviation, s = 17.3dB
Answer: For a total eclipse of the Sun to happen, the Moon must get directly in front of the Sun, as seen from Earth.
Explanation: solar eclipse occurs when something comes between the earth and the sun, casting it's shadow on the surface the earth. For the the sun to be blocked completely. The obstructing body must come directly between.