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Maru [420]
3 years ago
12

Un camión viaja en una carretera recta con un valor de velocidad de 100km/h y frena con una aceleración constante de valor numér

ico de 2.27m/s². ¿Cuánto viajo antes de detenerse?
Physics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Con la cinematica podemos encontrar la distancia recorrida antes de detenerse es  169,96 m

Parámetros dados

  • velocidad del camión v= 100 km/h
  • aceleración a= 2,27 m/s²  

Para encontrar

  • La distancia para detenerse

El sistema internacional de medidas (SI) es el sistema que deben tener todas las unidades del ejercicio, este es el primer paso si se tiene una mezcla de unidades

       v= 100 km/h ( 1000 m/1 km) ( 1 h/3600 s) = 27,78 m/s

La cinemática estudia el movimiento de los cuerpos, estableciendo relaciones entre la posición, la velocidad y la aceleración

          v² = v₀² – 2 a x

Donde v y v₀ son las velocidades inicial y final, a la aceleración del cuerpo y x la distancia recorrida

En este caso como el vehículo se detiene su velocidad final es cero

          0= v₀² – 2 a x

          x = \frac{v_o^2}{2a}

Calculemos

         x = 27,78² / 2 2,27

         x =  169,96 m

En conclusión usando la cinematica podemos encontrar la distancia recorrida antes de detenerse es

         x= 169,96 m

Aprender mas acerca de cinemática aquí:  

brainly.com/question/11298125

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