Answer: 0.137 m/s
Explanation:
from the question we are given the following
mass of train A (Ma) = 150,000 kg
velocity of train A (Va) = 0.3 m/s
mass of train B (Mb) = 95,000 kg
velocity of train B (Vb) = -0.12 m/s
final velocity (V) = ?
mass of both trains = 245,000 kg
- to solve this question we apply the conservation of momentum
MaVa + MbVb = (Ma + Mb) x V
V = (MaVa + MbVb) / (Ma + Mb)
V = ((150,000 x 0.3) + (95,000 x (-0.12))) / (245,000)
V = -33600 / 245,000
V = 0.137 m/s
Answer has to be b but I may be wrong
Answer:
a) 5 m from the finish line
b) 4875 s
Explanation:
distance = 1 km
tortoise speed = 0.2 m/s
speed of hare = 8 m/s
time take by hare t reach 0.8 km =
time taken by tortoise to travel 1 km =
time taken by the hare to travel 0.2 km =
time taken by the tortoise to travel 0.2 km =
distance traveled by tortoise in 25 second = 25 × 0.2 = 5 m
a) when tortoise is 5 m from the finish line then hare will resume the race.
b) the hare will be stationary for = 5000 - 125 = 4875 s
Q out = Q in
Q mix = Q water
mcΔt sand + mcΔt water = mcΔt water
30.2 x 2.01 x (29.3-12.1) + 87.7 x 4.19 x (29.3-12.1)=m x 4.19 x (85.8-29.3)
1044.07+6320.36=m x 236.74
m = 31.11 g
Hi there!
Use the following equation: (Newton's Second Law)
∑F = ma, where:
∑F = net force (J)
m = mass (kg)
a = acceleration (m/s²)
Plug in the given values:
∑F = 1500 · 40 = <em>60,000 J</em>