The density of an object is the ratio of its mass over the volume. This translates to the amount of substance present in a certain space and can mathematically be expressed as,
density = mass / volume
In this item, we are given that the object of mass 1.41 kg is able to displace 0.314 L of liquid. The volume of water displaced is also the volume of the object. Hence,
density = 1.41 kg / 0.314 L = 4.49 kg/L
Then, we convert the calculated volume of g/mL.
density = (4.49 kg/L)(1 L / 1000 mL)(1000 g/1 kg)
<em> density = 4.49 g/mL</em>
Answer:
clouds from when moist, warm rising air cools and expands in the atmosphere. The water vapor in the air condenses to form tiny water droplets which are the basis of clouds.
Explanation:
Answer:
A) E = 0N/C
B) 0i + 0^^j
C) F = 0N
D) 0^i + 0^j
Explanation:
You assume that the rings are in the zy plane but in different positions.
Furthermore, you can consider that the origin of coordinates is at the midway between the rings.
A) In order to calculate the magnitude of the electric field at the middle of the rings, you take into account that the electric field produced by each ring at the origin is opposite to each other and parallel to the x axis.
You use the following formula for the electric field produced by a charge ring at a perpendicular distance of r:
(1)
k: Coulomb's constant = 8.98*10^9Nm^2/C
Q: charge of the ring
r: perpendicular distance to the center of the ring
R: radius of the ring
You use the equation (1) to calculate the net electric field at the midpoint between the rings:

The electric field produced by each ring has the same magnitude but opposite direction, then, the net electric field is zero.
B) The direction of the electric field is 0^i + 0^j
C) The magnitude of the force on a proton at the midpoint between the rings is:

D) The direction of the force is 0^i + 0^j
Because a lot of things only live on earth earth is a place where all living this can live in
Answer:
The fringes are 4.7*10^-7 m apart, such that they are adjacent.
Explanation:
Using the formula for adjacent fringes given a single slit:
Δ
Δ
Δ
Hope this helps!