Answer:
11.025m
Explanation:
Using kinematics,
u = Initial velocity = 0.
t = Time taken = 1.5sec.
a = Acceleration from gravity = 9.8m/s^2
Distance = s
= ut + 1/2 * a * t^2
= 0 + 1/2 * 9.8 * (1.5)^2
= 11.025m
1. 0.5g*t^2 = 2010 m.
4.9t^2 = 2010.
t = 20.3 s. = Fall time.
D = Xo*t. = 193m/s * 20.3s = 3909 m.
2. V=sqrt(Xo^2+Yo^2)=sqrt(193^2+58^2) = 202 m/s.
3. Vo*t + 0.5g*t^2 = 2010 m.
58*t + 4.9*t^2 = 2010.
4.9t^2 + 58t - 2010 = 0.
Use Quadratic Formula.
t = 15.2 s. = Fall time.
D = 193m/s * 15.2s = 2934 m.
Answer:11 km/s
Explanation:
Given
Escape velocity at the surface of earth is 11 km/s
Escape velocity is given by
Escape velocity at the surface of earth
--------------------1
If Escape velocity is three times and the radius is also the three times
i.e. 
A dependent variable could be oxi clean because it needs water to work.
