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Zielflug [23.3K]
3 years ago
5

A 0.675 kg mass is attached to a

Physics
1 answer:
Yuki888 [10]3 years ago
3 0

Answer:

<h2>T= 0.6 sec</h2>

Explanation:

This problem bothers on the simple harmonic motion of a loaded spring

Given data

mass attached, m= 0-.675 kg

spring constant, k= 72.4 N/m

the period of oscillation can be solved for using the formula bellow

T= 2\pi \sqrt{\frac{m}{k} }

Substituting the given data into the expression above we have

T= 2*3.142\sqrt{\frac{0.675}{72.4} }\\T= 6.284*\sqrt{0.0093 }\\T= 0.6

T= 0.6 sec

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