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pshichka [43]
3 years ago
13

Anyo

Mathematics
1 answer:
marusya05 [52]3 years ago
5 0

Answer:

(√2+1 )(√2+3 )

(√2×√2)+(√2×3)+(1×√2)+(1×3)

2+3√2+√2+3 = 5+4√2

=5+4√2

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A swimming pool has has to be drained for maintenance the pool shaped like a cylinder with a diameter of 8 meters and a depth of
Alexandra [31]
<span>Step 1: find the radius
The radius is half of the diameter. So the radius is 8 because the diameter is 16.

Step 2: square the radius.
8^2 = 64

Step 3: plug into formula
pi * radius squared * height
3.14 * (64) * (1.8) = 361.728 m^3
The volume of the pool is 361. 728 meters cubed.

Step 4: Divide volume by the amount pumped out per hour
volume / amount pumped out = amount of hours
361.728/16 = 22.608 hours.


So your answer is approximately 23 hours.</span><span> </span>
6 0
3 years ago
Read 2 more answers
Gary spent $48 on a watch. He spent 1/3 of the remainder on a pen if he still had 1/2 of his money left,how much money did he ha
xeze [42]
T= total
<span>Money spent is: </span>
48+ 1/3 (T-48) = 1/2 T
One equation for one unknown, solve:

48 + 1/3 T -1/3*48= 1/2 T
48 - 16 =1/2 T- 1/3 T
32= 1/6 T
T= 6*32
<span>T=192

</span>192-48=144 money left after watch
1/3*144=48 third of leftover, spent on pen
<span>144-48=96 left which is half of 192. </span>
6 0
4 years ago
Read 2 more answers
What is the positive square root of 16?​
vekshin1

Answer:

4

Step-by-step explanation:

because The square root of 16 is 4, which is a rational number.

5 0
3 years ago
Read 2 more answers
A house is built on coordinates (2,9). There is a water pipeline that runs along the line y = 2 3 x – 1. What is the approximate
Basile [38]

Answer:

7.21 units

Step-by-step explanation:

The shortest length needed to connect the house to the existing pipeline is the perpendicular distance between the location of the house (2,9) and the line y = 2/3x - 1.

The perpendicular distance (d) between a point (x_1,y_1) and the line Ax + By + C  = 0 is given as:

d=\frac{|Ax_1+By_1+C|}{\sqrt{A^2+B^2} }

The line is given by y = 2/3 x - 1; 2/3x - y - 1 = 0. The point = (2, 9)

hence A = 2/3, B = -1, C = -1, x_1=2,y_1=9\\. Therefore:

d=\frac{|\frac{2}{3}(2)+(-1)(9)+(-1) |}{\sqrt{\frac{2}{3}^2+(-1)^2 } } \\\\d=7.21

4 0
3 years ago
Solve the equation<br><br> Hey guys can i get some help on this one? thanks!
eimsori [14]

Answer:

look at the picture i have sent

8 0
3 years ago
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