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horsena [70]
2 years ago
9

Use the equation: 2Mg + O2→ 2MgO

Chemistry
1 answer:
ludmilkaskok [199]2 years ago
6 0

Answer:

3 moles of O2 needed

Explanation:

2 moles of Mg   to one mole O2

   so 3 moles of O2 needed

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Calculate the molar mass of CH4 gas at STP when 5.46Lof the gas weighs 4g??​
meriva

Answer:

About 16.42 grams

Explanation:

PV=nRT \\\\(1)(5.46L)=n(0.0821)(273) \\\\n\approx 0.2436 \\\\4g/0.2436\approx 16.42

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6 0
3 years ago
PLEASE HELP!!
LUCKY_DIMON [66]

Answer:

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2 years ago
Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

Read more about rate constant

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5 0
2 years ago
HELP ASAP PLEASE!!!! 15 PTS!!
Bond [772]
ADD THEM all, and then divide by four. Thats what I would do! 
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3 years ago
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The location where the mercury level of the barometer would be the lowest is at the very high altitudes of the Earth's atmosphere (about 100 km), since air pressure decreases as altitude increases.
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3 years ago
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