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horsena [70]
1 year ago
9

Use the equation: 2Mg + O2→ 2MgO

Chemistry
1 answer:
ludmilkaskok [199]1 year ago
6 0

Answer:

3 moles of O2 needed

Explanation:

2 moles of Mg   to one mole O2

   so 3 moles of O2 needed

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How many grams of K2CO3 are needed to prepare a 400.0 mL of a 4.25M solution?
Basile [38]

Answer:

235 g

Explanation:

From the question;

  • Volume is 400.0 mL
  • Molarity of a solution is 4.25 M

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we know that;

Molarity = Number of moles ÷ Volume

Therefore;

First we determine the number of moles of the solute;

Moles = Molarity × volume

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Mass = Moles × Molar mass

Molar mass of  K₂CO₃, is 138.205 g/mol

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Thus, the mass of  K₂CO₃ needed is 235 g

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