Question

What is the molarity of 820 ml of kl solution that contains 36.52 g of kl

Answer 1

Answer: 0.27 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n = moles of solute

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{36.52g}{166g/mol}=0.22moles$

$V_s$ =volume of solution in ml

Molarity =$\frac{0.22\times 1000}{820ml}=0.27M$

The molarity of the solution is 0.27 M.

Answer 2

The formula is molarity (M) = moles / liters

molarity (M) = ?

1/ mass = 36.52 g of KCl (you need to find the mole)

mole = mass / Molar mass

Molar mass of KCl:

K = 39.10 g/mol

Cl = 35.45 g/mol

Add K and Cl together: 39.10 + 35.45 = 74.55 g/mol

mole = 36.52 g of KCl / 74.55 g/mol

mole = 0.489 mol of KCl

2/ Volume = 820 mL ( you need to convert to L)

820 / 1000 = 0.82 L

=> M = mol / L

    M = 0.489 mol / 0.82 L

    M = 0.59 mol/L

Hope this help!