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g100num [7]
3 years ago
9

What is the molarity of 820 ml of kl solution that contains 36.52 g of kl

Chemistry
2 answers:
andrew-mc [135]3 years ago
6 0

Answer: 0.27 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{36.52g}{166g/mol}=0.22moles

V_s =volume of solution in ml

Molarity =\frac{0.22\times 1000}{820ml}=0.27M

The molarity of the solution is 0.27 M.

oksian1 [2.3K]3 years ago
5 0

The formula is molarity (M) = moles / liters

molarity (M) = ?

1/ mass = 36.52 g of KCl (you need to find the mole)

mole = mass / Molar mass

Molar mass of KCl:

K = 39.10 g/mol

Cl = 35.45 g/mol

Add K and Cl together: 39.10 + 35.45 = 74.55 g/mol

mole = 36.52 g of KCl / 74.55 g/mol

mole = 0.489 mol of KCl

2/ Volume = 820 mL ( you need to convert to L)

820 / 1000 = 0.82 L

=> M = mol / L

    M = 0.489 mol / 0.82 L

    M = 0.59 mol/L

Hope this help!


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1) After adding 15.0 mL of the HCl solution, the mixture is before the equivalence point on the titration curve.

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nNaOH=\frac{0.25mol}{L} .10.0 \times 10^{-3} L=2.5 \times 10^{-3}mol

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Initial          2.5 × 10⁻³         1.5 × 10⁻³               0                      0

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