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cluponka [151]
3 years ago
9

A barometer measures the pressure of the atmosphere at different altitudes. Identify the location where the column of mercury is

lowest in the barometer.

Chemistry
2 answers:
Ghella [55]3 years ago
6 0
The location where the mercury level of the barometer would be the lowest is at the very high altitudes of the Earth's atmosphere (about 100 km), since air pressure decreases as altitude increases.
sineoko [7]3 years ago
5 0

Answer:

the mercury would be lowest at location 4.

Explanation: this is because pressure and altitudes have inverse relationship at the troposphere. higher altitude has lower pressure. also pressure at location 4 contribute to pressure at location 1. but pressure at location 1 do not contribute to pressure at location 4.

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4 0
3 years ago
1) A mixture of anhydrous sodium carbonate and sodium hydrogencarbonate of mass 10.000 g was heated until it reached a constant
vodomira [7]

The masses of the components are obtained as;

  • Sodium hydrogen carbonate = 3.51 g
  • Sodium carbonate =  8.708 g
<h3>What is decomposition?</h3>

The term decomposition has to do with the breakdown of the given substance into its components. The components of sodium hydrogen carbonate could be identified as water vapor, carbon dioxide gas and sodium carbonate. Among these products that have been listed here, we can see that it is only the sodium carbonate that remains as a solid. The others are gases that move away from the system that is under study.

Now putting down the equation of the reaction, we have;

2NaHCO_{3} (s) ----- > Na_{2} CO_{3} (s) + CO_{2} (g) + H_{2} O(g)

Now, the loss in  mass must be due to the carbon dioxide and the water. Hence we obtain the loss in mass to be 10.000 g -  8.708 g = 1.292 g

Mass of sodium hydrogen carbonate = 2 * 88 g/mol * 1.292 g/62 g/mol

= 3.51 g

Learn more about anhydrous sodium carbonate :brainly.com/question/20479996

#SPJ1

6 0
1 year ago
What is the freezing point depression of a solution that contains 0.705?
Sveta_85 [38]
Colligative properties calculations are used for this type of problem. Calculations are as follows:<span>
</span>

<span>ΔT(freezing point)  = (Kf)m
ΔT(freezing point)  = 1.86 °C kg / mol (0.705)
ΔT(freezing point)  = 1.3113 °C

</span>

<span>
</span>

<span>Hope this answers the question. Have a nice day.</span>

6 0
3 years ago
A black hole can be considered a star that has
lubasha [3.4K]
The first option, collapsed in on itself. The star's core mass becomes so dense that the resulting gravity implodes the star. Interesting enough, the third option is kindof true too...some large and tenacious black holes that absorb other stars will form incredibly bright accretion disks around their perimeter before filling absorbing the star.
7 0
3 years ago
Convert 55.6 km to m <br> show equation
crimeas [40]

Explanation:

1 km = 1000m

55.6 km = x m

x = 55.6*1000

x = 55600m

5 0
3 years ago
Read 2 more answers
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