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Ugo [173]
2 years ago
10

Compare both images located above. Which of the two is an elastic collision and

Chemistry
1 answer:
ANEK [815]2 years ago
5 0

Answer:

वृद्धा का मूल शब्द और प्रत्यय शब्द

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Please help me out...
liq [111]

Answer:

Explanation:

To convert from grams to atoms, first divide by the molar mass, the multiply by 6.022*10^23.

To convert from moles to mass, multiply by the molar mass of the element.

Hope this helps!

-Emma Victoria

4 0
2 years ago
Which process would require the least amount of energy?
Aleksandr [31]
Answer:<span> a) the process for the first ionization energy
</span>
<span>Every time you take a electron you're requiring more and more energy. Expelling the first one will require less energy than expelling the second and the second will require less than the third, and so on.
When you take the first one, the atom becomes positive and with that the negative forces of the electron will be more attracted to the positive charge. The more electrons that are lost, the more positive this ion will become, causing it to be more difficult to separate the electrons from the atom.
</span>
8 0
3 years ago
What is the formula of the compounds Cl- and Na+
Whitepunk [10]
Na and Cl together form the compound
NaCl2

5 0
3 years ago
At what temperature does 0.019135 moles of Ne in a 878.3 mL container exert a pressure of 0.946 atm?
Reika [66]
<h3>Answer:</h3>

Temperature is 529.164 K

<h3>Explanation:</h3>

We are given

Number of moles of Ne (n) =  0.019135 moles

Volume (V) = 878.3 mL

Pressure (P) = 0.946 atm

We are required to calculate the temperature;

We can do this using the ideal gas law equation which is;

PV = nRT, where P is the pressure, n is the number of moles, V is the volume, R is the ideal gas constant (0.082057 Latm/mol/K) and T is the temperature.

From the equation;

T=\frac{PV}{nR}

T = \frac{(0.946)(0.8783)}{(0.082057)(0.019135)}

T=529.164 K

Therefore, the temperature will be 529.164 K.

5 0
3 years ago
Read 2 more answers
1. Write the chemical equation when excess chloride ion is added to aqueous solution of cobalt chloride. Note observed color of
Aneli [31]

The element cobalt can form compounds in two different oxidation states, +2 and +3. 


The +2 state is more common.

The ion Co2+ (aq) is pink.

Other compounds of cobalt(II), which include both anhydrous Co2+ and complex ions, are commonly blue.

If an aqueous solution contains both cobalt(II) and chloride ions, the blue ion CoCl42- forms, in equilibrium with the pink Co2+ (aq) ion.

<span>CoCl42- (aq) <===========> Co2+ (aq) + 4Cl1-(aq)</span>

5 0
3 years ago
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