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2 years ago

In 1828, the diameter of the U.S. dime was changed to approximately 18 mm. What is this diameter when expressed in micrometers

Engineering

1 answer:

neonofarm [45]2 years ago

7 0

The diameter of an 18 mm dine when expressed in micrometers is; 18000 micrometers

<h3>Conversion of Units</h3>

We are given the diameter of dime at 18 mm.

Now, from conversion of units between mm(millimeter) and micrometer, we know that;

1 millimeter = 1000 micrometer.

Thus, by proportion, 18 millimeter will be;

18 millimeters × 1000 micrometers/1 millimeter

>> 18000 micrometers

In conclusion, the diameter of the 18mm fine in micrometers is; 18000 micrometers

Read more about conversion of units at; brainly.com/question/8421470

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ValentinkaMS [17]

I think it is C because if have to send it to someone you would want them to be able to open it

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3 years ago

A 0.06-m3 rigid tank initially contains refrigerant- 134a at 0.8 MPa and 100 percent quality. The tank is connected by a valve t

lesantik [10]

Answer:

a) 0.50613

b) 22.639 kJ

Explanation:

From table A-11 , we will make use of the properties of Refrigerant R-13a at 24°C

first step : calculate the volume of R-13a ( values gotten from table A-11 )

V = m1 * v1 = 5 * 0.0008261 = 0.00413 m^3

next : calculate final specific volume ( v2 )

v2 = V / m2 = 0.00413 / 0.25 ≈ 0.01652 m^3/kg

<u>a) Calculate the mass of refrigerant that entered the tank </u>

v2 = Vf + x2 * Vfg

v2 = Vf + [ x2 * ( Vg - Vf ) ] ----- ( 1 )

where: Vf = 0.0008261 m^3/kg, V2 = 0.01652 m^3/kg , Vg = 0.031834 m^3/kg ( insert values into equation 1 above )

x2 = ( 0.01652 - 0.0008261 ) / 0.031834

= 0.50613 ( mass of refrigerant that entered tank )

<u>b) Calculate the amount of heat transfer </u>

Final specific internal energy = u2 = Uf + ( x2 + Ufg ) ----- ( 2 )

uf = 84.44 kj/kg , x2 = 0.50613 , Ufg = 158.65 Kj/kg

therefore U2 = 164.737 Kj/kg

The mass balance ( me ) = m1 - m2 --- ( 3 )

energy balance( Qin ) = ( m2 * u2 ) - ( m1 * u1 ) + ( m1 - m2 ) * he

therefore Qin = 41.184 - 422.2 + 403.655 = 22.639 kJ

3 0

3 years ago

Diffusion of Ammonia in an Aqueous Solution Ammonia (A)-water (B) solution ta 278 K and 4 mm thick is in contact with an organic

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Answer:

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The pictures below shows the whole explanation for the problem

4 0

4 years ago

A normal shock wave takes place during the flow of air at a Mach number of 1.8. The static pressure and temperature of the air u

Darina [25.2K]

Answer:

The pressure upstream and downstream of a shock wave are related as

$\frac{P_{1}}{P_{o}}=\frac{2\gamma M^{2}-(\gamma -1)}{\gamma +1}$

where,

$\gamma$ = Specific Heat ratio of air

M = Mach number upstream

We know that $\gamma _{air}=1.4$

Applying values we get

$\frac{P_{1}}{100kPa}=\frac{2\times 1.4\times 1.8^{2}-(1.4 -1)}{1.4 +1}\\\\\frac{P_{1}}{100kPa}=3.61\\\\\therefore P_{1}=361.33kPa(Absloute)$

Similarly the temperature downstream is obtained by the relation

$\frac{T_{1}}{T_{o}}=\frac{[2\gamma M^{2}-(\gamma -1)][(\gamma -1)M^{2}+2]}{(\gamma +1)^{2}M^{2}}$

Applying values we get

$\frac{T_{1}}{423}=\frac{[2\times 1.4\times 1.8^{2}-(1.4-1)][(1.4-1)1.8^{2}+2]}{(1.4+1)^{2}\times 1.8^{2}}\\\\\therefore \frac{T_{1}}{423}=1.53\\\\\therefore T_{1}=647.85K=374.85^{o}C$

The Mach number downstream is obtained by the relation

$M_{d}^{2}=\frac{(\gamma -1)M^{2}+2}{2\gamma M^{2}-(\gamma -1)}\\\\\therefore M_{d}^{2}=\frac{(1.40-1)\times 1.8^{2}+2}{2\times1.4\times 1.8^{2}-(1.4-1)}\\\\\therefore M_{d}^{2}=0.38\\\\M_{d}=0.616$

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4 years ago

Write a SELECT statement that returns one row for each customer that has orders with these columns: The email_address column fro

Dafna11 [192]

Answer:

The statement is as follows:

Explanation:

We had better avoid such correlated subqueries by instead using aggregation with GROUP BY:

SELECT

c.email_address,

COUNT(DISTINCT o.order_id) AS num_orders,

COALESCE(SUM(oi.quantity * (oi.item_price - oi.discount_amount)), 0) AS total_amount

FROM customers c

LEFT JOIN orders o

ON c.customer_id = o.customer_id

INNER JOIN order_items oi

ON o.order_id = oi.order_id

GROUP BY

c.customer_id,

c.email_address;

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3 years ago