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OleMash [197]
3 years ago
15

What type of circles have two or more circles with different center points?

Engineering
2 answers:
Assoli18 [71]3 years ago
6 0

Answer:

Concentric circles

Explanation:

Concentric circles are two or more circles which have the same center point. The region between two concentric circles is called an annulus.

lorasvet [3.4K]3 years ago
3 0
Concentric circles I think
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An incompressible viscous fluid flows through a pipe with a flow rate of 1 mL/s. The pipe has a uniform diameter D0 and a length
Nataly [62]

Answer:

Q_2 = 32 mL/s

Explanation:

Given :

The flow is incompressible viscous flow.

The initial flow rate, Q_1 = 1 mL/s

Initial diameter, D_1= D_0

Initial length, L_1=L_0

The initial pressure difference to maintain the flow, P_1=P_0

We know for a viscous flow,

$\Delta P = \frac{32 \mu V L}{D^2}$

$\Delta P = \frac{32 \mu Q L}{\frac{\pi}{4}D^4}$

$Q \propto \Delta P \times D^4$

$\frac{Q_1}{Q_2}= \frac{P_1}{P_2} \times \left( \frac{D_1}{D_2} \right)^4$

$\frac{1}{Q_2}= \frac{P_0}{2P_0} \times \left( \frac{D_0}{2D_0} \right)^4$

$\frac{1}{Q_2}= \frac{1}{2} \times \left( \frac{1}{2} \right)^4$

$\frac{1}{Q_2}= \frac{1}{32}$

∴ Q_2 = 32 mL/s

6 0
3 years ago
Define in detail Technology and Evolution in the context of your prior Knowledge?​
julsineya [31]

The technological evolution entails the transformation of society through technological development.

<h3>What is Technology?</h3>

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<h3>What is Evolution?</h3>

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Hence, the technological evolution entails the transformation of society through technological development.

In conclusion, the the new discoveries as a result of technology evolution primarily impacted the society on a positive level.

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2 years ago
Create a document that includes a constructor function named Company in the document head area. Include four properties in the C
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3 0
4 years ago
g a heat engine is located between thermal reservoirs at 400k and 1600k. the heat engine operates with an efficiency that is 70%
Bond [772]

Answer:

<em>Heat rejected to cold body = 3.81 kJ</em>

Explanation:

Temperature of hot thermal reservoir Th = 1600 K

Temperature of cold thermal reservoir Tc = 400 K

<em>efficiency of the Carnot's engine = 1 - </em>\frac{Tc}{Th}<em> </em>

eff. of the Carnot's engine = 1 - \frac{400}{600}

eff = 1 - 0.25 = 0.75

<em>efficiency of the heat engine = 70% of 0.75 = 0.525</em>

work done by heat engine = 2 kJ

<em>eff. of heat engine is gotten as = W/Q</em>

where W = work done by heat engine

Q = heat rejected by heat engine to lower temperature reservoir

from the equation, we can derive that

heat rejected Q = W/eff = 2/0.525 = <em>3.81 kJ</em>

6 0
3 years ago
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