'The coordinates of the endpoints of CD

Mathematics

1 answer:

Leona [35]3 years ago

8 0

$C(-4;-2);\ D(14;\ 2)\\\\the\ x-coordinate\ of\ the\ midpoint\ of\ CD:x=\frac{-4+14}{2}=\frac{12}{2}=6$

You might be interested in

Can some help me with this! Will Mark brainliest ❤️

Serhud [2]

If TU is 7.5 and UC is 17.5, TV = 25 because you just add the two together

3 0

2 years ago

Help me on this one please

shepuryov [24]

Answer:

The equation is set up wrong

Step-by-step explanation:

$9^{2} +b^{2} =15^{2}$

3 0

2 years ago

Help please ! What is the equation of the line?

olasank [31]

I think it’s y=1/2x +2

4 0

2 years ago

What is the factored form of x^3-1

polet [3.4K]

Answer:

the factors of x^3-1 are $x^3 -1 = (x-1) (x^2 +x+1)\\$

Step-by-step explanation:

We need to find factors of x^3 -1

$x^3-1 \\(x)^3 -(1)^3\\We \,\, know\,\, a^3 -b^3 = (a-b) (a^2 +ab + y^2) \\So, \,\, using\,\, the \,\, formula\,\,\\Here\,\, a= x \,\,and\,\, b= 1\\(x)^3 -(1)^3 = (x-1) (x^2 +x+1)\\$

So, the factors of x^3-1 are $x^3 -1 = (x-1) (x^2 +x+1)\\$

7 0

3 years ago

Explain in detail how to find the vertex: <br> y=-2x^2 + 2x + 3

Cerrena [4.2K]

$\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-2}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{+3} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right)$

$\bf \left(-\cfrac{2}{2(-2)}~~,~~3-\cfrac{2^2}{4(-2)} \right)\implies \left( \cfrac{1}{2}~~,~~3+\cfrac{4}{8} \right)\implies \left(\cfrac{1}{2}~~,~~\cfrac{28}{8} \right) \\\\\\ \left(\cfrac{1}{2}~~,~~\cfrac{7}{2} \right)\implies \left(\frac{1}{2}~,~3\frac{1}{2} \right)$

7 0

3 years ago