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4 years ago

A. -7x+5 B. -7x-35 C. -7x+35 D. x-35

Mathematics

2 answers:

Daniel [21]4 years ago

7 0

Answer:

Step-by-step explanation:

since p(x) = r(x) x s(x)

by substituting the given values ,

p(x)=(x+5) x -7

=-7x-35

liubo4ka [24]4 years ago

5 0

Answer:

Step-by-step explanation:

p(x) = r(x) * s(x)

= (x + 5) *(-7) {Use distributive property}

= x * -7 + 5 * -7

= - 7x - 35

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The sum of the squares of three consecutive positive integers is 7805. What is the sum of the cubes of the three original intege

Vitek1552 [10]

Answer:

398259

Step-by-step explanation:

Let from the given positive integers, x be the smallest integers,

Also, numbers are consecutive,

So, the second integer = x + 1,

Third integer = x + 2,

According to the question,

$x^2+(x+1)^2+(x+2)^2=7805$

$x^2+x^2+2x+1+x^2+4x+4=7805$

$3x^2+6x+5=7805$

$3x^2+6x+5-7805=0$

$3x^2+6x-7800=0$

$x^2+2x-2600$

By middle term splitting,

$x^2+(52-50)x-2600=0$

$x^2+52x-50x-2600=0$

$x(x+52)-50(x+52)=0$

$(x-50)(x+52)=0$

By zero product property,

x-50 = 0 or x + 52 =0

⇒ x = 50 or x = -52 ( not possible )

Hence, numbers are 50, 51, 52,

∵ (50)³ + (51)³ + (52)³ = 125000 + 132651 + 140608 = 398259

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juin [17]

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