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4 years ago

Which best describes the role of a secondary consumer in a food web?

Chemistry

2 answers:

podryga [215]4 years ago

8 0

Answer:

<u> Carnivore that feeds on primary consumers</u>

Mamont248 [21]4 years ago

3 0

Secondary consumers in a food web are carnivores that feed on primary consumers. Consumers are organisms that receive energy by eating other organisms. Specifically, primary consumers are those that feed on producers. Producers are those that are able to produce their own food, like plants. Meanwhile, secondary consumers, like humans, eat primary consumers such as cows.

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Calculate the molarity of 48.0 mL of 6.00 M H2SO4 diluted to 0.250 L

const2013 [10]

Answer:

The answer is 1.15m.

Since molality is defined as moles of solute divided by kg of solvent, we need to calculated the moles of H2SO4 and the mass of the solvent, which I presume is water.

We can find the number of H2SO4 moles by using its molarity

C=nV→nH2SO4=C⋅VH2SO4=6.00molesL⋅48.0⋅10−3L=0.288

Since water has a density of 1.00kgL, the mass of solvent is

m=ρ⋅Vwater=1.00kgL⋅0.250L=0.250 kg

Therefore, molality is

m=nmass.solvent=0.288moles0.250kg=1.15m

4 0

3 years ago

Read 2 more answers

Which is an example of diffraction?

jeyben [28]

I would say d but I’m not sure

8 0

3 years ago

Using the thermodynamic information in the ALEKS Data tab, calculate the boiling point of titanium tetrachloride . Round your an

ddd [48]

Answer:

The boiling point is 308.27 K (35.27°C)

Explanation:

The chemical reaction for the boiling of titanium tetrachloride is shown below:

Ti $Cl_{4(l)}$ ⇒ Ti $Cl_{4(g)}$

ΔH° $_{f}$ (Ti $Cl_{4(l)}$ ) = -804.2 kJ/mol

ΔH° $_{f}$ (Ti $Cl_{4(g)}$ ) = -763.2 kJ/mol

Therefore,

ΔH° $_{f}$ = ΔH° $_{f}$ (Ti $Cl_{4(g)}$ ) - ΔH° $_{f}$ (Ti $Cl_{4(l)}$ ) = -763.2 - (-804.2) = 41 kJ/mol = 41000 J/mol

Similarly,

s°(Ti $Cl_{4(l)}$ ) = 221.9 J/(mol*K)

s°(Ti $Cl_{4(g)}$ ) = 354.9 J/(mol*K)

Therefore,

s° = s° (Ti $Cl_{4(g)}$ ) - s°(Ti $Cl_{4(l)}$ ) = 354.9 - 221.9 = 133 J/(mol*K)

Thus, T = ΔH° $_{f}$ /s° = [41000 J/mol]/[133 J/(mol*K)] = 308. 27 K or 35.27°C

Therefore, the boiling point of titanium tetrachloride is 308.27 K or 35.27°C.

5 0

3 years ago

Im doing a science project and need examples and non-examples of an Atom. some examples of an atom is neon, hydrogen, argon, etc

gogolik [260]

Answer:

Anything not on the periodic table is an element non example! ... So, for a substance to be an element, all of its atoms must have the same number of protons. Examples of elements include hydrogen, lithium, nickel, and radium.

Explanation:

6 0

3 years ago

At what point in time (A ,B or C) is the reaction the fastest? How do you know?

gladu [14]

Don’t click that link EVER, they try to use your camera fsr

4 0

3 years ago