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3 years ago

What is the modification of the small intestinal wall that serves to increase surface area?

Chemistry

1 answer:

astra-53 [7]3 years ago

4 0

Answer:

Villi

Explanation:

Villi are folds on the small intestine lining that increase the surface area to facilitate the absorption of nutrients.

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What is the wavelength of radiation emitted when an electron goes from the n = 7 to the n = 4 level of the Bohr hydrogen atom? G

Phantasy [73]

Answer:

the wavelength of radiation emitted is $\mathbf{\lambda= 2169.62 \ nm}$

Explanation:

The energy of the Bohr's hydrogen atom can be expressed with the formula:

$\mathtt{E_n =- \dfrac{13.6\ ev}{n^2}}$

For n = 7:

$\mathtt{E_7 =- \dfrac{13.6\ ev}{7^2}}$

$\mathtt{E_7 =-0.27755 \ eV}$

For n = 4

$\mathtt{E_4=- \dfrac{13.6\ ev}{4^2}}$

$\mathtt{E_4 =- 0.85\ eV}$

The electron goes from the n = 7 to the n = 4, then :

$\mathtt{E_7-E_4 = (-0.27755 - (-0.85) ) \ eV}$

$\mathtt{= 0.57245\ eV}$

Wavelength of the radiation emitted:

$\mathtt{\lambda= \dfrac{hc}{0.57245 \ eV}}$

where;

hc = 1242 eV.nm

$\mathtt{\lambda= \dfrac{1242 \ eV.nm }{0.57245 \ eV}}$

$\mathbf{\lambda= 2169.62 \ nm}$

4 0

2 years ago

Select the answer that lists the radiation waves in order of increasing

lubasha [3.4K]

D. microwaves, Ultraviolet, x-rays

3 0

3 years ago

Read 2 more answers

Claude Bernard first recognized _____.

storchak [24]

Answer : Option B) Plant stomata opening and closing to maintain homeostasis.

Explanation : Claude Bernand was a French Physiologist who first discovered about "homeostasis" which is defined as the controlled stability of the internal milieu, or internal environment, of cells and tissues in plants.

In plants stomatal opening and closing was done for maintaining homeostasis with the external and internal plant environment.

3 0

2 years ago

How Is disaccharide is hydrolyzed into monosaccharides

PolarNik [594]

The disaccharides are broken down into monosaccharides by enzymes called maltases, sucrases, and lactases, which are also present in the brush border of the small intestinal wall. Maltase breaks down maltose into glucose.

6 0

2 years ago

Two unknown molecular compounds were being studied. A solution containing 5.00 g of compound A in 100. g of water froze at a low

Shtirlitz [24]

Answer:

Compound B.

Explanation:

The freezing point depression is a colligative property. It depends on the number of particles (moles) present in the solution.

$\Delta T_{\text{f}} = K_{\text{f}} b$