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hjlf
3 years ago
11

What is the modification of the small intestinal wall that serves to increase surface area?

Chemistry
1 answer:
astra-53 [7]3 years ago
4 0

Answer:

Villi

Explanation:

Villi are folds on the small intestine lining that increase the surface area to facilitate the absorption of nutrients.

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#1: A concentration in terms of volume/volume is used to describe which of the following types of solutions?
DanielleElmas [232]
B.
This method of expressing concentration is employed with solutions where both the solute and solvent are liquid. This is because it is easy to measure the volume of a liquid compared to that of a solid. Usually weight/weight is used in concentrations involving only solids.
5 0
3 years ago
Read 2 more answers
Combustion analysis of a 13.42-g sample of the unknown organic compound (which contains only carbon, hydrogen, and oxygen) produ
pentagon [3]

Answer: molecular formula = C12H16O8

Explanation:

NB Mm CO2= 44g/mol

Mm H2O= 18g/mol

Moles of CO2 = 36.86/44=0.84mol

0.84mole of CO2 has 0.84 mol of C

Moles of H2O = 10.06/18= 0.56mol

1mol of H20 contains 1mol of O and 2 mol H,

Hence there are 0.56mol O and (0.56×2)mol H

Hence the compound contains

C= 0.84 mol H= 1.12mol O=0.56mol

Divide through by smallest number

C= 0.83/0.56= 1.5mol

H= 1.12/0.55= 2mol

O= 0.56/0.56= 1mol

Multiply all by 2 to have whole number of moles = 3:4:2

Hence empirical formula= C3H4O2

(C3H4O2)n = 288.38

[(12×3) + 4+(16×2)]n= 288.38

72n=288.38

n= 4

:. Molecular formula=(C3H4O2)4= C12H16O8

7 0
3 years ago
What is the correct name for the molecular compound n2s4?
blsea [12.9K]
Dinitrogen tetrasulfide
3 0
3 years ago
A twenty-eight-liter volume of gas contains 11 g methane, 1.5-gram nitrogen and 16-gram carbon dioxide. Determine partial pressu
GREYUIT [131]

Based on Dalton's Law, for a mixture of gases, the total pressure is the sum of the partial pressure of each gas.

Partial pressure (p) of each gas is related to the total pressure (P) as follows:

p = X * P----------(1)

where X is the mole fraction of that gas

X = moles of a particular gas/total number of moles of all gases in the mixture--------------(2)

Step 1: Calculate the moles of each gas

Mass of methane, CH4 = 11 g

Mass of nitrogen, N2 = 1.4 g

Mass of carbon dioxide, CO2 = 16 g

# moles of CH4 = 11 g/16 gmol-1 = 0.6875

# moles of N2 = 1.4/28 = 0.05

# moles of CO2 = 16/44 = 0.3636

Total moles = 0.6875+0.05+0.3636 = 1.1011

Step2: Calculate mole fractions of each gas

Based on equation (2)

X(CH4) = 0.6875/1.1011 = 0.6244

X(N2) = 0.05/1.1011 = 0.0454

X(CO2) = 0.3636/1.1011 = 0.3302

Step 3: Calculate the total pressure

Based on ideal gas equation:

PV = nRT

given that;

V = 28 L

n = total moles = 1.1011

R = gas constant = 0.0821 Latm/mol-K

Since temp T is not given, let us consider room temperature of 25 C = 25 + 273 = 298 K

Now, P = nRT/V = 1.011*0.0821*298/28 = 0.962 atm

Step 3: Calculate partial pressures

Based on equation:

p(CH4) = 0.6244*0.962 atm = 0.601 atm

P(N2) = 0.0454*0.962 atm = 0.044 atm

P(CO2) = 0.3302*0.962 atm = 0.318 atm


4 0
3 years ago
Magbigay ng 3 halimbawa ng lipunang sibil. Paki sagot ng wasto plies >_<​
Sliva [168]

Answer:

i not anther stand your bla bla bla

6 0
3 years ago
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