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1 year ago

A dog’s weight dropped to 62 kg after its weight decreased by 7%. What was the dog’s original weight?

Mathematics

1 answer:

Alinara [238K]1 year ago

5 0

Answer:

original weight= mass/weight

62kg/7

Step-by-step explanation:

8.85 original weight

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How many times does 291 go into 4?

Musya8 [376]

Answer: I think it's 72.75

Step-by-step explanation:

You divide 291 and 4 and it equals 72.75

<h3>I dont know if it's the actual answer but i hope this helps :)</h3>

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3 years ago

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What is (x^-2 y^10)^2/x^5 y^-3 using only positive exponents

Eddi Din [679]

Answer:

$\frac{(x^{ - 2}{y}^{10})^{2} }{ {x}^{5} {y}^{ - 3} } \\ \frac{ {x}^{ - 4} {y}^{20} }{ {x}^{5} {y}^{ - 3 } } \\ {x}^{ - 9} {y}^{23} \\ \frac{ {y}^{23} }{ {x}^{9} } \\ ans \: c$

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1 year ago

I need helpp its my final exam

Mashcka [7]

Answer:

hey i believe that your answer is A. without having to do the math if you look at it you can tell that its bigger then options B and C so those are not it. and it is to small to be D. so with that said your answer is A have a nice dy and good luck!

Step-by-step explanation:

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2 years ago

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Solve the equation. Then check your solution

kondaur [170]

Answer:

Option B is correct i.e. 21

Step-by-step explanation:

In the question we're provided with an equation that is :

v/7 = 3

And we are asked to find the solution for the equation .

Solution : -

 $\longrightarrow \: \frac{v}{7} = 3$ 

Multiplying by 7 on both sides :

$\longrightarrow \: \frac{v}{ \cancel{7} }\times \cancel{7} = 3 \times 7$

On further calculations , we get :

$\longrightarrow \: \blue{\boxed{v = 21}}$

Therefore , solution for equation is 21 .That means option B is the correct answer.

Verifying :

We are verifying our answer by substituting value of v in the equation given in question :

$\longrightarrow \: \frac{v}{7} = 3$

Putting value of v :

$\longrightarrow \: \cancel{\frac{21}{7}} = 3$

By dividing 21 with 7 , we get :

$\longrightarrow \:3 = 3$

$\longrightarrow \: L.H.S=R.H.S$

$\longrightarrow \: Hence , \: Verified.$

Therefore , our answer is valid .

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The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff.

zhuklara [117]

$\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ h(t)=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{19}t+110~\hspace{10em}19~\frac{ft}{sec}$

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