Answer:-2/5, -3/4, 0, 3/4, 19/10, 8/3
Step-by-step explanation:
Use photo math, it will help you with your answer a lot more.
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
<4 = 22
Step-by-step explanation:
<4 = x
x + 158 = 180
x = 22
Answer:
1= 2,400 feet
2= 154 meters
3= 120 pints
4= 2. 056 centigrams
5= 16.1 C
6= 50F
7= -2.8C
1= multiply the length value by 3
2= divide the length value by 10
3= multiply the volume value by 8
4= divide the mass value by 10
5= Take the °F temperature and subtract 32. Multiply this number by 5. Divide this number by 9 to obtain your answer in °C.
6= multiply the temperature in degrees Celsius by 2, and then add 30 to get the (estimated) temperature in degrees Fahrenheit.
