Dependent probability

100 POINTS BRAINLIEST QUESTION ATTACHED.

Dimas [21]

ANSWER

$- 7 \sqrt{6}$

EXPLANATION

The given radical expression is

$3 \sqrt{6} - 10 \sqrt{2} \times \sqrt{3}$

Recall and use

$\sqrt{a} \times \sqrt{b} = \sqrt{ab}$

to obtain;

$3 \sqrt{6} -10 \sqrt{2 \times 3}$

Simplify the second radicand.

$3 \sqrt{6} - 10 \sqrt{6}$

We have two like surds so we can simplify to obtain;

$- 7 \sqrt{6}$

3 0

3 years ago

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a recipe requires 1/2 cup of flour for every batch of cookies how many full batches of cookies can be made with 5 1/2 cups of fl

Fantom [35]

Hello There!

You want to know how many cookies can be made using 5 1/2 cups of flour.

$Solving$

1 x 2 2
-------------- = -----
2 x 11 22

2/22 simplified is 1/11

So, You can make 11 cookies with 5 1/2 cups of flour.

Hope this helped!

4 0

3 years ago

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The probability that a certain hockey team will win any given game is 0.3773 based on their 13 year win history of 389 wins out

notsponge [240]

Answer:

0.8895 = 88.95% probability that the hockey team wins at least 3 games in November.

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the teams wins, or they do not win. The probability of the team winning a game is independent of any other game, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3773.

This means that $p = 0.3773$

Their schedule for November contains 12 games.

This means that $n = 12$

Find the probability that the hockey team wins at least 3 games in November.

This is:

$P(X \geq 3) = 1 - P(X < 3)$

In which:

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.3773)^{0}.(0.6227)^{12} = 0.0034$

$P(X = 1) = C_{12,1}.(0.3773)^{1}.(0.6227)^{11} = 0.0247$

$P(X = 2) = C_{12,2}.(0.3773)^{2}.(0.6227)^{10} = 0.0824$

Then

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0034 + 0.0247 + 0.0824 = 0.1105$

$P(X \geq 3) = 1 - P(X < 3) = 1 - 0.1105 = 0.8895$

0.8895 = 88.95% probability that the hockey team wins at least 3 games in November.

3 0

2 years ago

Combine like terms to find the equivalent expression to 6(5/8u+1)-6(-7/4u-5)

IgorLugansk [536]

Answer:

B

Step-by-step explanation:

Distribute 6 to 5/8u and 1 and you get 15/4u + 6. Distribute -6 to -7/4u and -5 and you get 21/2u and 30. The equation will be 15/4u + 6 + 21/2u + 30 and then combine like terms to get 57/4u + 36.

6 0

3 years ago

A function hall charges $250 fee to rent the hall plus $15 per guest.vwrite an equation for this function

m_a_m_a [10]

Answer:

y=15x+250 (x is the number of guests)

Step-by-step explanation:

the 15 is the slope, so that is the number that has to be multiplied by. The 250 is an additional fee that doesn't change, so it's just added on.

7 0

2 years ago

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