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OverLord2011 [107]
1 year ago
7

At the end of the day, you finish a job only to find that the user you were doing it for had to leave. What should you do

Computers and Technology
1 answer:
Vika [28.1K]1 year ago
7 0

The way to proceed in the situation presented would be:

  • Finish the process started to help that user and continue with the other tasks of the day.

<h3>How to serve a customer properly?</h3>

In different work positions we have the possibility of personally or virtually assisting clients by carrying out procedures to help them improve their service or experience with the company.

Companies have developed complete customer service systems so that their employees know how to proceed in different specific situations in which their customers require help.

In the situation described, the most appropriate thing would be to finish the process required by the user and continue with the other tasks of the day that were planned.

Learn more about job in: brainly.com/question/2018598

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Create a brief program that demonstrates use of a Java exception. For example, you could use InputMismatchException and ask the
HACTEHA [7]

Answer:

Here is the program that demonstrates the use of JAVA exception:

import java.util.Scanner;  //to accept input from user

public class Main {  //class name

   public static void main(String[] args) {  //start of main method

      Scanner input = new java.util.Scanner(System.in);  //creates Scanner class object to accept input from user

       int number1 = 0;  //stores the first integer value

       int number2 = 0;  //stores the second integer value

       while(true) {  //keeps looping until user enters integer value

           System.out.println("Enter 2 integers to perform addition: "); //prompts user to enter two integer values

           try {  //defines a chunk of code to check for errors        

               number1 = input.nextInt(); //reads input integer 1

               number2 = input.nextInt(); //reads input integer 2                  

               break;             }  

           catch (java.util.InputMismatchException e) { // defines a code chunk to execute if an error occurs in the try code chunk

              System.out.println("Input must be an integer "); //displays this message if user enters anything other than an integer value

              input.nextLine();              }         }  // reads input from user again until user enters both integer type values

       System.out.println("The sum is: " + (number1+number2));      }  } //if user enters 2 integers then computes and displays the sum of two integer values

Explanation:

The program uses InputMismatchException exception and asks the user to input two integers and computes the sum of two integers if user enters  integers otherwise an exception InputMismatchException is thrown and a error message Input must be an integer is displayed to the user if they input a string of letters instead o f integer values. Here while loop is used which keeps executing until user enters both the integer values. After the user enters correct values, the sum of the two integers are computed and result is displayed on output screen. The screenshot of program and its output is attached.

Another program asks the user to input an integer and the program executes correctly if they enter an integer but exception InputMismatchException is thrown with an error message that is is displayed to the user if they input a string of letters. Here is the program:

import java.util.Scanner;

public class Main {

   public static void main(String[] args) {

       Scanner input = new java.util.Scanner(System.in);

       int number1 = 0;          

       while(true) {

           System.out.println("Enter an integer value: ");        

           try {

               number1 = input.nextInt();  

               break;             }  

           catch (java.util.InputMismatchException e) {

              System.out.println("Input must be an integer ");

              input.nextLine();             }        }  

       System.out.println("The program executed correctly!");  } }

7 0
3 years ago
How many base cases are in the functionabove?
baherus [9]

Answer:

The answer is (b). 1.

Explanation:

In the code there is only 1 base case .

the base case is as following:-

if(n==0)

return 0;

this is the base case.

Base case is the most important statement in the function that uses recursion because without base case the recursion calls will keep on going and we will get a run time error.

5 0
2 years ago
What is the output of the code below?
sp2606 [1]

Answer:

The output of the given code is 56.43

Explanation:

As the code is given in java language the following are the code

public class code

{

public static void main(String[] args)

{

double num = 56.4321;

System.out.print("%.2f", 56.4321);

}

}

The %f means that it print the floating point number and .2 means that it print the first two digit of the given number after the point .

so " %.2f "means that it print the value first 2 digit of floating point number after the point .

Therefore it print 56.43

7 0
3 years ago
Write an application that reads an English-language phrase and encodes it into Morse code. Also write an application that reads
Morgarella [4.7K]

Answer: English to Morse code. Hello my name is Isabella:   .... . .-.. .-.. --- / -- -.-- / -. .- -- . / .. ... / .. ... .- -... . .-.. .-.. .-

Morse code to English: .. / .-.. .. -.- . / -- .- - ....  is I like math

6 0
2 years ago
In an email message, a name stored in the contact list or the email address of the original sender appears in the
Vadim26 [7]
The name or email address of the original sender will appear in the from line. The email is sent by that person, that is who the email is from.
7 0
3 years ago
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