All categories

2 years ago

Help!!!!!!! v is a vector of magnitude 4 making an angle of 30° with the positive x-axis. find v in component form .

1 answer:

5 0

Since v is a vector of magnitude 4 and makes angle 30° with the positive x axis, vector v in component form is v = 2√3i + 2j

To find vector v in component form, we need to know what a vector is

<h3>What is a vector?</h3>

A vector is a physical quantity that has both magnitude and direction.

<h3>Component of a vector</h3>

A vector can be resolved into perpendicular components along the x, y and z axis.

<h3>Components of vector v</h3>

Since vector v has a magnitude of 4 making an angle of 30 with the positive x - axis, its x-component is V = (vcos30°)i

= (4cos30°)i

= (4 × √3/2)i

= 2√3i.

The y-component of v is V' = (vsin30°)j

= (4 × sin30°)j

= (4 × 1/2)j

= 2j

<h3>Vector v in component form</h3>

So, vector v in component form is v = V + V'

= 2√3i + 2j

So, since v is a vector of magnitude 4 and makes angle 30° with the positive x axis, vector v in component form is v = 2√3i + 2j

Learn more about vectors here:

brainly.com/question/25705666

You might be interested in

rewona [7]

X = 5/3 and m∠SPY = 8 1/3°.

Since PQ bisects the angle, the two angles formed by the bisector are equal:

11/2x - 5 = 4x - 5/2

We will first multiply everything by 2 to eliminate the fractions:
(11/2x)*2 - 5*2 = 4x*2 - (5/2)*2
11x - 10 = 8x - 5

Subtract 8x from each side:
11x - 10 - 8x = 8x - 5 - 8x
3x - 10 = -5

Add 10 to both sides:
3x - 10 + 10 = -5 + 10
3x = 5

Divide both sides by 3:
3x/3 = 5/3
x = 5/3

Now we will plug this in for x in both smaller angles and add them together to find the measure of ∠SPY:

11/2(5/3) - 5 + 4(5/3) - 5/2
55/6 - 5 + 20/3 - 5/2

We will rewrite everything using a denominator of 6:
55/6 - 30/6 + 40/6 - 15/6 = (55-30+40-15)/6 = 50/6 = 8 2/6 = 8 1/3°

3 0

3 years ago

I dont understand the circled question ....please help!

irina1246 [14]

Parallel lines NEVER intersect/meet, this is because they have the same slope and they go in the same direction.

These lines are parallel because they have the same slopes of 3/4 (because they go 3 units up and 4 units to the right. slope = rise/run)

7 0

3 years ago

What is the measure of < A?<br><br> 93<br> 113<br> 138<br> 180

aleksley [76]

The answer is a
180-87
=93

4 0

3 years ago

Help ! solve the following system of equations <br><br> -9x+2y=-13<br><br> 2x-9y=20

Stella [2.4K]

Answer: x = 1, y = -2

Step-by-step explanation:

-9x+2y=-13

x= 13/9 + 2/9y

2x-9y=20

2(13/9+2/9y)-9y=20

<em>Substitute y with -2.</em>

<em />

x= 13/9+2/9(-2)

<em>After solving you'll see that 1 is a possible solution for x.</em>

<em />

Check your answer

-9x+2y=-13

-9x1+2(-2) = -13

2x-9y=20

2x1-9(-2) = 20

-13 = -13

20 = 20

Therefore, x=1 and y=-2

5 0

3 years ago

Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65

erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 2.65

$\sigma$ = standard deviation = 0.85

n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

P(X bar <= 3) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{3-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{3-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z < 2.06) = 0.98030

P(X bar <= 2.65) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3) = 0.98030 - 0.5 = 0.4803 .

8 0

4 years ago