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Lunna [17]
2 years ago
9

Determine the number of real number solutions for the equation x^2-2x+6=0​

Health
1 answer:
Reika [66]2 years ago
3 0

x^2 - 2x + 6 = 0

Use the quadratic formula

x= <u>-b + or - squareroot b^2- 4 (a)(c)</u>

                     all over 2a

a = 1

b = -2

c = 6

x= <u>-(-2)+ or - squareroot (-2)^2 - 4(1)(6)</u>             x=  <u>2 + or - squareroot of -20</u>

              all over 2 times 1                                                2

x= -20 <---- NO SOLUTION

Hope this helps :))

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