A swimming pool reading reports that chlorine is present at 130 ppm. How many grams of chlorine are present per liter of pool wa
1 answer:
130 ppm will contain 0.12985167 grams of chlorine present in per liter of pool water.
<h3>What is ppm?</h3>This is an abbreviation for "parts per million" and it also can be expressed as milligrams per liter (mg/L).
1001.142303 ppm is equal to 1 g/L
So, 130 ppm will contain grams of chlorine present in per liter of pool water which is equal to 0.12985167 gram/L.
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The concentration in mol L-l (M) = 0.717
<h3>Further explanation</h3>Given
12% solution of tetrahydrate magnesium chloride (MgCl₂)
Required
The concentration
Solution
Tetrahydrate magnesium chloride (MgCl₂)⇒MgCl₂.4H₂O
MW = Ar Mg+2. Ar Cl+8. Ar H + 4. Ar O
MW=24.31 + 2 x 35.45 + 8 x 1.01 + 4 x 16
MW=24.31+70.9+8.08+64
MW=167.29 g/mol
12% solution = 12 % m/v = 12 g in 100 ml solution
For 1 L solution :
The concentration in g/L = 120 g/L
Convert grams to moles :