All categories

3 years ago

1.Grassland are where most of our_____ comes from?

Chemistry

2 answers:

-Dominant- [34]3 years ago

6 0

The answer is B. Crops used as food

Dafna11 [192]3 years ago

3 0

Answer is B.crops used as food

You might be interested in

1.00 pint of milk has a volume of how many milliliters

zlopas [31]

I searched it up on Google and I got 473.176 Hope this helps.

3 0

3 years ago

How many moles of glucose (C6H12O6) are in 1.5 liters of a 4.5 M C6H12O6 solution?

zepelin [54]

For the answer to the question above asking, how many moles of glucose (C6H12O6) are in 1.5 liters of a 4.5 M C6H12O6 solution?
The answer to your question is the the third one among the given choices which is 6.8 mol.
moles glucose = 1.5 x 4.5 = 6.8

3 0

3 years ago

Read 2 more answers

1. Marisa determined the melting point of a substance to be 24.5C. Find the percent error of her measurement if the actual melti

USPshnik [31]

Answer:

$\%\ Error = 21.5\%$

Explanation:

Given

$Measured = 24.5$

$Actual = 31.2$

Required

Determine the percentage error

First, we need to determine the difference in the measurement

$Difference = |Actual - Measured|$

$Difference = |31.2 - 24.5|$

$Difference = |6.7|$

$Difference = 6.7$

The percentage error is calculated as thus:

$\%\ Error = \frac{Difference * 100\%}{Actual}$

$\%\ Error = \frac{6.7 * 100\%}{31.2}$

$\%\ Error = \frac{670\%}{31.2}$

$\%\ Error = 21.4743589744\%$

$\%\ Error = 21.5\%$ approximated

6 0

3 years ago

If a 58 g sample of metal at 100 c is placed into calorimeter containing 60g of water at 18 c , the temperature of the water inc

tatiyna

Answer:

The water will absorb 1004.16 Joule of heat

Explanation:

Step 1: Data given

Mass of the metal = 58.00 grams

Temperature of the metal = 100.00 °C

Mass of water = 60.00 grams

Temperature of water = 18.00 °C

Final temperature = 22.00 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate the amount of heat absorbed by the water in joules

Q = mass *specific heat *ΔT

⇒ with Q = the heat absorbed by water

⇒ with mass of water = 60.00 grams

⇒ with specific heat of water = 4.184 J/g°C

⇒ with ΔT = The change in temperature of water = T2 - T1 = 22 - 18 = 4.0 °C

Q = 60.00 * 4.184 J/g°C * 4.0 °C

Q = 1004.16 J

The water will absorb 1004.16 Joule of heat

6 0

3 years ago

If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the of strontium-90 is ________ yr.

lesantik [10]

The question is incomplete, here is the complete question.

If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the half-life of strontium-90 is ________ yr.

a. 28.8 b. 30.9 c. 35.4 d. 32.2

Answer : The half-life of strontium-90 is 28.8 years.

Explanation :

This is a type of radioactive decay and all radioactive decays follow first order kinetics.

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by :

$k=\frac{2.303}{t}\log\frac{a}{a-x}$

where,

k = rate constant

t = time taken for decay process = 9.00 year

a = initial amount or moles of the reactant = 1.000 g

a - x = amount or moles left after decay process = 0.805 g

Putting values in above equation, we get:

$k=\frac{2.303}{9.00}\log\frac{1.00}{0.805}$

$k=0.0241\text{ year}^{-1}$

To calculate the half-life, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$0.0241\text{ year}^{-1}=\frac{0.693}{t_{1/2}}$

$t_{1/2}=28.8\text{ years}$

Therefore, the half-life of strontium-90 is 28.8 years.

5 0

3 years ago