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Softa [21]
1 year ago
12

Why wouldn't the concorde travel lower

Chemistry
1 answer:
Alika [10]1 year ago
5 0

Supersonic flight over land is typically forbidden to minimize disruption to people on the ground. This meant that until it was over open water, Concorde could not operate at its maximum Mach 2 capability.

<h3>What is Concorde?</h3>
  • The Concorde is a tailless aircraft with a drooping nose, an oval delta wing, and a narrow fuselage that allows for seating for 92 to 128 passengers.
  • It's improbable that Concorde will ever fly for an airline again in a commercial capacity. The economics of reactivating Concorde and incorporating it into the fleet of a contemporary airline would be challenging to justify, even if the technical and regulatory concerns could be handled.
  • Supersonic flight over land is usually not allowed to minimize the impact on people on the ground. This meant that Concorde could not operate at its maximum Mach 2 speed until it was over an open body of water.

To learn more about Concorde refer to:

brainly.com/question/14354579

#SPJ1

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Within atoms, what kind of energy<br> is stored?
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Chemical energy is stored within atoms
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For Carbon - 14, the top number will be ____. The bottom number will be ____.
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16 and 6

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the top number will be 16 and the bottom number will be 6

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A student observes the combustion (burning) of propane (C3H8). Because of the heat and light it generates, the student concludes
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Answer:

The student's conclusion is not correct

Explanation:

Activation energy is the minimum amount of energy required for a reaction to occur. All reactions require there activation energy to be met before the reaction can proceed. When the temperature of a reaction is increased, the kinetic energy of the reactant molecules increases; colliding more with each other, which makes them "surmount" the activation energy of the reaction faster as compared to a lower temperature.

In combustion, there is burning of an hydrocarbon (in this case propane) in excess oxygen. The burning assists in increasing the kinetic energy of the reactant particles which in turn easily surmounts the activation energy of the reaction  by colliding (effective collision) more with oxygen. So, the reaction has an activation energy but the activation energy has been met and passed and hence the reaction is proceeding faster.

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7 0
3 years ago
My professor gave me two questions to solve using the Van Der Waals Equation. She told us to solve for P and the second one we h
Fed [463]

Answer:

P=atm

b=\frac{L}{mol}

Explanation:

The problem give you the Van Der Waals equation:

(P+\frac{n^{2}a}{V^{2}})(V-nb)=nRT

First we are going to solve for P:

(P+\frac{n^{2}a}{V^{2}})=\frac{nRT}{(V-nb)}

P=\frac{nRT}{(V-nb)}-\frac{n^{2}a}{v^{2}}

Then you should know all the units of each term of the equation, that is:

P=atm

n=mol

R=\frac{L.atm}{mol.K}

a=atm\frac{L^{2}}{mol^{2}}

b=\frac{L}{mol}

T=K

V=L

where atm=atmosphere, L=litters, K=kelvin

Now, you should replace the units in the equation for each value:

P=\frac{(mol)(\frac{L.atm}{mol.K})(K)}{L-(mol)(\frac{L}{mol})}-\frac{(mol^{2})(\frac{atm.L^{2}}{mol^{2}})}{L^{2}}

Then you should multiply and eliminate the same units which they are dividing each other (Please see the photo below), so you have:

P=\frac{L.atm}{L-L}-atm

Then operate the fraction subtraction:

P=P=\frac{L.atm-L.atm}{L}

P=\frac{L.atm}{L}

And finally you can find the answer:

P=atm

Now solving for b:

(P+\frac{n^{2}a}{V^{2}})(V-nb)=nRT

(V-nb)=\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}

nb=V-\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}

b=\frac{V-\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}}{n}

Replacing units:

b=\frac{L-\frac{(mol).(\frac{L.atm}{mol.K}).K}{(atm+\frac{mol^{2}.\frac{atm.L^{2}}{mol^{2}}}{L^{2}})}}{mol}

Multiplying and dividing units,(please see the second photo below), we have:

b=\frac{L-\frac{L.atm}{atm}}{mol}

b=\frac{L-L}{mol}

b=\frac{L}{mol}

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