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2 years ago

B(1)= 160, b(n) = b(n-1) * 0.5 for n (g/e) 2 determine the first 4 items in a sequence given this recursive formula.

Mathematics

1 answer:

Paul [167]2 years ago

7 0

Answer:

160

Step-by-step explanation:

You start with the first term that is given which would be

b(1)=<u><em>160</em></u>

That would be our first term, then we multiply by 0.5 which would be 1/2

which gives us 80 as it is a division

You take the next term that we have found (80) and then we do the same thing, multiply by 0.5 (1/2)

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Solve f (x) = 32^x+6•1/2 = 8^x-1

emmainna [20.7K]

Option B: The value of x is -16

Explanation:

Given that the equation $f(x)=32^{x+6} \cdot \frac{1}{2}=8^{x-1}$

We need to determine the value of x.

Let us substitute f(x) = 0, then we have,

$32^{x+6} \cdot \frac{1}{2}=8^{x-1}$

Now, we shall determine the value of x.

The term $8^{x-1}$ can be written as $\left(2^{3}\right)^{x-1}$

Hence, we have,

$32^{x+6} \cdot \frac{1}{2}=\left(2^{3}\right)^{x-1}$

Also, the term $32^{x+6}$ can be written as $\left(2^{5}\right)^{x+6}$

Thus, we have,

$\left(2^{5}\right)^{x+6} \frac{1}{2}=\left(2^{3}\right)^{x-1}$

Applying the exponent rule, $\left(a^{b}\right)^{c}=a^{b c}$ , we have,

$2^{5(x+6)} \cdot \frac{1}{2}=2^{3(x-1)}$

$2^{5(x+6)} \cdot 2^{-1}=2^{3(x-1)}$

If $a^{f(x)}=a^{g(x)}$ then $f(x)=g(x)$

$5(x+6)-1=3(x-1)$

Simplifying, we get,

$5x+30-1=3x-3$

$5x+29=3x-3$

$2x+29=-3$

$2x=-32$

$x=-16$

Therefore, the value of x is -16

Hence, Option B is the correct answer.

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This is the answer

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yawa3891 [41]

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-BARSIC- [3]

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