For circle h, jn = 3, nk = x, ln = 2, and nm = 6. solve for x. circle h with chords jk and lm intersecting at n inside the circl e 9 1 5 4
1 answer:
The circle is an illustration of intersecting chords .
The value of x is 4
<h3>How to determine the value of x?</h3>
The given parameters are:
Chords: jk and lm Point of intersection = n jn = 3, nk = x, ln = 2, and nm = 6
This means that:
jn * nk = ln * nm
So, we have:
3 * x = 2 * 6
Divide both sides by 3
x = 2 * 2
Evaluate the product
x = 4
Hence, the value of x is 4
Read more about intersecting chords at:
brainly.com/question/13950364
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