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Marizza181 [45]
3 years ago
9

If you want to prepare 2.00 L of a 0.800 M NaNO_3 solution from a NaNO_3 stock solution that is 1.5 M in concentration, how many

mL of the stock solution must you start with
Chemistry
1 answer:
Leya [2.2K]3 years ago
3 0

1066.7 ml of the stock solution must start with, preparing 2.00 L of a 0.800 M NaNO3 solution.

<h3>What is volume?</h3>

Volume is the space occupied by a three-dimensional object.

By the formula \rm M_1V_1= M_2V_2

M1 is the initial molarity, 1.5 M

M2 is the final molarity, 0.800 M

V1 is the initial volume

V2 is the final volume, 2.00 L

Putting the values in the equation

\rm 1.5\;M \times V_1= 0.800\;M \times 2.00\;L\\\\V_1 = \dfrac{ 0.800\;M \times 2.00\;L}{1.5\;M} = 1066.7\;ml

Thus, the initial volume is 1066.7 ml

Learn more about volume

brainly.com/question/1578538

#SPJ1

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<h3>E) Two of the above statements are true.</h3>
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