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castortr0y [4]
3 years ago
10

1) In the boxes below, draw the model given in the simulation and draw a model of the molecules in an object when the object

Chemistry
1 answer:
sladkih [1.3K]3 years ago
6 0

The molecules of the cold element are going to be closer together and still than the molecules of the hot element because the heat energy causes the molecules to be stimulated and to move.

<h3>How do molecules act at different temperatures?
</h3>

In the image you can see the behavior of the molecules when they are in different environments. On the right you see the cold molecules and on the left the hot molecules that are characterized by the following characteristics:

Cold molecules:

  • Molecules together.
  • Molecules with little movement.

Hot molecules:

  • Separate molecules.
  • Molecules with active movement.

A simple example to understand this behavior of molecules is water because:

  • When water is frozen its molecules are almost static and close together.
  • When the water is liquid and it is heated, the molecules move and that is why the water has bubbles, its molecules are separated.

Learn more about molecules in: brainly.com/question/19922822

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In the reaction 2H2O (1)+ 2Cl^- (aq)= H2(g)+Cl2 (g)+ 2OH^-(aq), which substance is reduced?
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Answer:- C. H

Explanations:- Reduction is gain of electron. In other words we could say that decrease in oxidation number is reduction.

As per the rules, oxidation number of hydrogen in its compounds is +1(except metal hydrides) and the oxidation number of oxygen in its compounds is -2.

The oxidation number in elemental form is zero.

In H_2O , the oxidation number of H is +1 and oxidation number of O is -2. Oxidation number of Cl in Cl^- is -1. On product side, the oxidation number of hydrogen in H_2 is zero and in OH^- the oxidation number of H is +1 and that of O is -2. Oxidation number of Cl in Cl_2 is 0.

From above data, Oxidation number of O is -2 on both sides so it is not reduced.

Oxidation number of Cl is changing from -1 to 0 which is oxidation.

Oxidation number of H is changing from +1 to 0 which is reduction.

So, the right choice is C.H

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