Answer:
b I think if it's wronged sorry
The final temperature of the water is determined as 50.55 ⁰C.
<h3>
Final temperature of the water</h3>
The final temperature of the water is determined from the following calculations;
Q = mcΔθ
Δθ = Q/mc
where;
- Q is the amount of energy = 81 kcal = 338904 J
- c is specific heat capacity of water = 4,200 J/kgC
Δθ = 338904 /(3.5 x 4200)
Δθ = 23.05 °C
Final temperature = T₁ + Δθ
Final temperature = 27.5°C + 23.05 °C = 50.55 ⁰C.
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In calculating the change in enthalpy in a certain reaction, it is important to remember that it is the sum of the enthapy of formation for the substances involved in the reaction.
<span>CaO(s)+2HCl(aq)→CaCl2(aq)+H2O(l) ΔH= –186kJ
</span>Ca(OH)2(aq) → CaO(s)+H2O(l)<span> ΔH= 65.1 kJ
</span>Ca(OH)2(aq) + 2HCl(aq) → CaCl2(aq) + 2H2O(l) ΔH= -120.9 kJ
Answer:
74.09 atm
Explanation:
Using the gas laws ( Charles and Boyle's law). We have the formula ,
P1/T1 = P2/T2
Where P1 = 30.3atm
T1 = -100 degree Celsius
to kelvin = -100+ 273 = 173K
T2 = 150 degree Celsius
To Kelvin = 150 = 150+273 = 423K
Imputing values
P1/T1 = P2/T2
30.3/173 = P2/ 423
Cross multiply
173×P2 = 30.3 ×423
173P2 = 12816.9
Divide both sides by 173
P2 = 12816.9/173
P2 = 74.09 atm
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Explanation:
Copper has an atomic number of 29, so it contains 29 protons and 29 electrons. ... The atomic weight of copper is 64; it has 29 protons and 35 neutrons.