Explanation:
Method of prepration of sodium thiosulphate - definition
In the laboratory, this salt can be prepared by heating an aqueous solution of sodium sulphite with sulphur or by boiling aqueous NaOH and sulfur according to this equation:
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Answer: " 13.5 g Al " ;
→ that is: "13.5 grams of aluminum."
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Explanation:
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<u>Note</u>: What is missing from the question is the "balanced chemical equation" for the "chemical reaction" that contains:
The reactants: "aluminum (Al) " ; and "chlorine (Cl) " ; and:
The product: "aluminum choloride (AlCl₃) " .
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The "balanced chemical equation" is:
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2 Al + 3 Cl₂ → 2 AlCl₃ ;
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<u>Note</u>: The molecular weight of "aluminum (Al)" is: " 26.98 g /mol " .
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So: We call solve using a technique known as: "dimensional analysis" :
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0.500 mol AlCl₃ *
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<u>Note</u>: The units of "mol AlCl₃" cancel out to "1' ; and:
The units of "mol Al" cancel out to "1" ; and we are left with:
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" g Al ["grams of aluminum"] ;
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<u>Note</u>: We can "cancel out the "2's" ; since "2/2 = 1 " ; and we have:
→ (0.500 * 26.98) g Al ;
= 13.49 g Al ;
→ Round to 3 (Three) significant figures;
→ Since: "0.500" has 3 (Three) significant figures:
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= 13.5 g Al ; that is: "13.5 grams of aluminum."
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