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ohaa [14]
2 years ago
6

You select an F1 male chicken that resulted from a cross of a slow feathering female to a wild-type male. You cross this F1 male

to a wild-type female to form an F2. What genotypes do the parental and F1 birds have, and what proportions do you predict in the F2
Biology
1 answer:
nevsk [136]2 years ago
6 0

If the parental genotypes are homzygous, the F1 birds would be heterozygous while all the F2 offspring would have the wild-type phenotype.

<h3>Monohybrid crossing</h3>

Based on the assumption that the wild-type genotype is AA and the slow feathering genotype is aa.

A cross between AA and aa:

                                  AA    x    aa

                  F1          Aa   Aa   Aa   Aa

One F1 male (Aa) is then crossed with a wild-type female (AA):

                                 Aa    x    AA

                               AA   AA   Aa   Aa

Genotypic proportion: 2 AA:2 Aa

Phenotypic proportion = 100% wild-type

More on monohybrid crossing can be found here: brainly.com/question/1185199

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