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Sati [7]
2 years ago
7

Which response best completes the following IF-ELSE statement?

Computers and Technology
1 answer:
Svetllana [295]2 years ago
8 0

Answer:

Congratulations!

Explanation:

You might be interested in
The function below takes one parameter: a string (date_string) containing a date in the mm/dd/year format. Complete the function
Natalija [7]

Answer:

The solution code is written in Python 3.

  1. def convertDate(date_string):
  2.    date_list = date_string.split("/")
  3.    for i in range(0, len(date_list)):
  4.        date_list[i] = int(date_list[i])
  5.    return date_list  
  6. print(convertDate('06/11/1930'))

Explanation:

Firstly, create a function convertDate() with one parameter, <em>date_string</em>. (Line 1).

Next, use the Python string <em>split()</em> method to split the date string into a list of date components (month, day & year) and assign it to variable <em>date_list</em>. (Line 3) In this case, we use "/" as the separator.

However, all the separated date components in the <em>date_list</em> are still a string. We can use for-loop to traverse through each of the element within the list and convert each of them to integer using Python<em> int() </em>function. (Line 5 - 6)

At last return the final date_list as the output (Line 8)

We can test our function as in Line 11. We shall see the output is as follow:

[6, 11, 1930]

8 0
3 years ago
In order to allow communication between vlans for exchange of data what must be used?​
lana66690 [7]
<span>In order to allow communication between vlans for exchange of data what must be used?

Router must be used</span>
4 0
3 years ago
You are building a network and need to connect five computers in an office. They will be on the same network segment and you sho
lilavasa [31]

Answer:

a lan party

Explanation:

because it's your personal party

4 0
3 years ago
The value of the mathematical constant e can be expressed as an infinite series: e=1+1/1!+1/2!+1/3!+... Write a program that app
LUCKY_DIMON [66]

Answer:

// here is code in c++ to find the approx value of "e".

#include <bits/stdc++.h>

using namespace std;

// function to find factorial of a number

double fact(int n){

double f =1.0;

// if n=0 then return 1

if(n==0)

return 1;

for(int a=1;a<=n;++a)

       f = f *a;

// return the factorial of number

return f;

}

// driver function

int main()

{

// variable

int n;

double sum=0;

cout<<"enter n:";

// read the value of n

cin>>n;

// Calculate the sum of the series

  for (int x = 0; x <= n; x++)

  {

     sum += 1.0/fact(x);

  }

  // print the approx value of "e"

    cout<<"Approx Value of e is: "<<sum<<endl;

return 0;

}

Explanation:

Read the value of "n" from user. Declare and initialize variable "sum" to store the sum of series.Create a function to Calculate the factorial of a given number. Calculate the sum of all the term of the series 1+1/1!+1/2!.....+1/n!.This will be the approx value of "e".

Output:

enter n:12

Approx Value of e is: 2.71828

6 0
3 years ago
Write a program that records high-score data for a fictitious game. the program will ask the user to enter five names, and five
Harman [31]

Scores.cpp

#include <iostream>

#include <string>

using namespace std;

void initializeArrays(string names[], int scores[], int size);

void sortData(string names[], int scores[], int size);

void displayData(const string names[], const int scores[], int size);

int main()

{

   string names[5];

   int scores[5];

   //reading names and scores

   initializeArrays(names, scores, 5);

   //sorting the lists based on score.

   sortData(names, scores, 5);

   //displaying the contents of both arrays

   displayData(names, scores, 5);

 

  return 0;

}

void initializeArrays(string names[], int scores[], int size){

   for(int i=0; i<size; i++){

       cout<<"Enter the name for score #"<<(i+1)<<": ";

       cin >> names[i];

       cout<<"Enter the score for score #"<<(i+1)<<": ";

       cin >> scores[i];

       }

}

void sortData(string names[], int scores[], int size){

   

       int temp = 0;

       string tempStr = "";

       

       for(int i=0; i < size; i++){

               for(int j=1; j < (size-i); j++){

                      //checking max score and sorting based on it.

                       if(scores[j-1]< scores[j]){

                               //swap the elements!

                           //swapping scores

                               temp = scores[j-1];

                               scores[j-1] = scores[j];

                               scores[j]=temp;

                               

                               //swapping names

                               tempStr = names[j-1];

                               names[j-1] = names[j];

                               names[j]=tempStr;

                       }

                       

               }

       }

}

void displayData(const string names[], const int scores[], int size){

   cout<<"Top Scorers:"<<endl;

       //printing the elements up to the size of both arrays.

       for(int i=0; i<size; i++){

           cout<<names[i]<<": "<<scores[i]<<endl;

       }

}

3 0
3 years ago
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