Answer:
because an individual molecule of sugar weighs more than and individual molecule of water. So one molecule of water will have a smaller mass than one molecule of sugar , since it contains fewer atoms
Answer:
ATP, Mitochondria, Cellular respiration.
Explanation:
The Krebs cycle of, cellular respiration, in the mitochondria results to the an accumulation of protons in the inter-membrane space of the organelle. This proton motive force is harnessed in the electron transport chain by ATP synthase to generate ATPs.
Answer:
Water molecules pull the sodium and chloride ions apart, breaking the ionic bond that held them together. After the salt compounds are pulled apart, the sodium and chloride atoms are surrounded by water molecules, as this diagram shows. Once this happens, the salt is dissolved, resulting in a homogeneous solution.
Explanation:
Hope this Helps :)
Brainliest pls? Have a good day/night
Hmm i think it might be a <span>covalent </span>bond
I hope you have a wonderful day! And hope this helps! :D
Answer:
Interspecific competition
Explanation:
Interspecific competition occurs when two different species occupy the same environment as they coexist and depend on the same limited resources for survival. As a result of these limited resources, there's competition between the different species with each species having their different levels of fitness. Their level of fitness determines how well they will complete with other species. This will also determine if they will go extinct or thrive in such environment where there's interspecific competition.
The graph given shows the growth of the relative population size of two different species grown together.
It shows that P. aurelia, with time, outcompetes P. coudatum.
This graph clearly suggest that interspecific competition has occurred. Both species are competing for the same limited resources.
P. aurelia has a greater fitness which enables it to outcompete the other species sharing the same environment with it.
Interspecific competition beats describes the relationship between the two species in graph B.