Answer:
The six codons for arginine are the following:
GCA, GCG, GCT, GCC, TCT, TCC
A) Considering the individual bases in each codon, three mutations are possible at each base position. Hence, 3 × 3 × 6 = 54 mutations are possible.
B) Considering the mutations at the 3rd base: 3 × 4 + 1 × 2 = 14 of these mutations are silent mutations.
C) Lysine codons are the following:
TTT, TTC
There are two possible mutations that can give a lys codon.
Hope that answers the question, have a great day!
Answer:
The DNA strands unwind, and RNA polymerase binds to the template strand.
The synthesis of mRNA begins.
The mRNA undergoes intron splicing and exits the nucleus.
The tRNA moves through mRNA with the activated amino acids. attached to it.
The amino acids assemble.
Explanation:
there
Answer:
Bacteria are eukaryotes
They have a single DNA,circular chromosome
Explanation:
It's their basic characteristics that they share .
Theses are what the Nurse should include:
•sodium or salt
• meat(some kind of protein)
•grains like bread or corn flakes cereal
•exactly one serving
•dairy low in phosphorus
• fruit and juice from concentrate
