<span>Answer:
Nothing is balanced in your final equation: not H, not O, not Cr, not I and your charges aren't either.
Start with your 2 half reactions:
I- --> IO3-
Cr2O72- --> 2 Cr3+
Balance O by adding H2O:
I- + 3 H2O --> IO3-
Cr2O72- --> 2 Cr3+ + 7H2O
Balance H by adding H+:
I- + 3 H2O --> IO3- + 6 H+
Cr2O72- + 14 H+ --> 2 Cr3+ + 7H2O
Balance charge by adding e-:
I- + 3 H2O --> IO3- + 6 H+ + 6 e-
Cr2O72- + 14 H+ + 6 e- --> 2 Cr3+ + 7H2O
Since the numbers of electrons in your two half reactions are the same, just add them and simplify to give:
Cr2O72- + I- + 8 H+ --> IO3- + 2 Cr3+ + 4 H2O</span>
Answer:
Explanation:
Assuming that all caculations are at normal pressure and -1.72°C :
Where
is the number of moles of hydrogen
is the mass of hydrogen
is the density of hydrogen
That's cool man, you should study more... wheres the question though?
Answer:
Cu
Fe
Explanation:
Oxidizing agents:
Oxidizing agents oxidize the other elements and itself gets reduced.
Reducing agents:
Reducing agents reduced the other element are it self gets oxidized.
Oxidation:
Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.
Reduction:
Reduction involve the gain of electron and oxidation number is decreased.
a) Cu²⁺ (aq) + Mg(s) + Cu(s) + Mg²⁺(aq)
Copper is oxidizing agent it accept two electrons from magnesium and oxidize the Mg and itself get reduced.
b) Fe₂O₃(s) + 3CO(g) → 2Fe(l) + 3CO₂(g)
In this reaction iron is oxidizing agent because iron itself reduced from +3 to 0.
Answer:
Heat of vaporization: 250.580 kJ/mol. Number of Protons/Electrons: 47. Number of neutrons: 61. Classification: Transition Metal.
Number of Protons/Electrons: 47
Number of neutrons: 61
Classification: Transition Metal
Number of shells: 5
Explanation:
add 47 to 61 and its 108! hope its right! have a great day!
