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andriy [413]
3 years ago
8

a gas thermometer measure temperature by measuring the pressure of a gas inside the fixed volume container a thermometer reads a

pressure of 248 torr at 0 degrees Celsius what is the temperature when the thermometer reads a pressure of 345 torr
Chemistry
1 answer:
sdas [7]3 years ago
6 0

Hello!

a gas thermometer measure temperature by measuring the pressure of a gas inside the fixed volume container a thermometer reads a pressure of 248 torr at 0 degrees Celsius what is the temperature when the thermometer reads a pressure of 345 torr

We have the following information:

P1 (initial pressure) = 248 torr

T1 (initial temperature) = 0 ºC (in Kelvin)

TK = TºC + 273.15 → TK = 0 + 273.15 → T1 (initial temperature) = 273.15 K

P2 (final pressure) = 345 torr

T2 (final temperature) = ? (in Kelvin)

According to the Law of Charles and Gay-Lussac in the study of gases, we have an isochoric (or isovolumetric) transformation when its volume remains constant or equal, then we will have the following formula:

\dfrac{P_1}{T_1} = \dfrac{P_2}{T_2}

\dfrac{248}{273.15} = \dfrac{345}{T_2}

248*T_2 = 345*273.15

248\:T_2 = 94236.75

T_2 = \dfrac{94236.75}{248}

T_2 = 379.9868952... \to \boxed{\boxed{T_2 \approx 380\:K}}\end{array}}\qquad\checkmark

If you want the solution in Celsius Temperature, we have:

TC = TK - 273.15

TC = 380 - 273.15

TC =  106.85 → Temperature = 106.85 ºC

_______________________________

I Hope this helps, greetings ... Dexteright02! =)

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3 years ago
A 32 L samples of xenon gas at 10°C is expanded to 35 L. Calculate the final temperature.
morpeh [17]

Answer:

              Final Temperature = 36.54 ⁰C

Explanation:

Lets suppose the gas is acting ideally, then according to Charle's Law, "<em>The volume of a fixed mass of gas at constant pressure is directly proportional to the absolute temperature</em>". Mathematically for initial and final states the relation is as follow,

                                                V₁ / T₁  =  V₂ / T₂

Data Given;

                  V₁  =  32 L

                  T₁  =  10 °C = 283.15 K             ∴ K = °C + 273.15

                  V₂  =  35 L

                  T₂  =  ??

Solving equation for T₂,

                         T₂  =  V₂ × T₁  / V₁

Putting values,

                         T₂  =  (35 L × 283.15 K) ÷ 32 L

                         T₂  =  309.69 K     ∴ ( 36.54 °C )

Result:

           As the volume is increased from 32 L to 35 L, therefore, the temperature must have increased from 10 °C to 36.54 °C.

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Explanation:

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As a result, formula of magnesium oxide is MgO and not MgO_{2}.

The student write the equation as Mg + O_2 \rightarrow MgO_2, it is not correct.

Therefore, given equation will be balanced as follows.

          2Mg + O_{2} \rightarrow 2MgO

Since, number of atoms on both reactant and product side are equal. Hence, this equation is completely balanced.

7 0
3 years ago
What information do we need to determine the molecular formula of a compound from the empirical formula?
defon

Answer:

Molecular mass

Explanation:

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,  

Molecular mass = n × Empirical mass

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6 0
3 years ago
Um.. i dont need help lol
Tasya [4]

Answer:

thats cool mate

Explanation:

hope ya have a good day, im answering just for the points tbh

7 0
2 years ago
Read 2 more answers
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