Explanation:
The given chemical reaction is:
The relation between Eo cell and Keq is shown below:
The value of Eo cell is:
Br- undergoes oxidation and I2 undergoes reduction.
Reduction takes place at cathode.
Oxidation takes place at anode.
Hence,
F=96485 C/mol
n=2 mol
R=8.314 J.K-1.mol-1
T=298K
Substitute all these values in the above formula:
Answer:
Keq=6.13x10^33
Answer:
20 mole of oxygen
Explanation:
1 mole of proprane reacts with 5 moles of oxygen so 4 time 5 equals 20
Answer:
Imo : Gas particles are in constant, random motion. The volume of gas particles is negligible in comparison to the volume of the container. There are no attractive forces between gas particles.
Answer:
B:Metamorphic
Explanation:
Rocks formed under high heat and pressure is essentially the definition of metamorphic rock :)
