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2 years ago

Which two properties apply to most elements that conducts heat: malleable, brittle, highly combustible, has free electrons

Chemistry

1 answer:

Airida [17]2 years ago

4 0

Answer:

malleable, has free electrons

Explanation:

The two properties that applies to most elements that conducts heat is that they are malleable and they have free electrons.

Most substances that conducts heat readily are metals.

Metals are held together by metallic bonding.
For a metallic bonds to form, there must be attraction between the positive nuclei of all the closely packed atoms in the lattice and the electron cloud jointly formed by all the atoms by losing their outermost shell electrons.
The physical properties of metals such as malleability and conduction is due to this bond type.

You might be interested in

In an ecosystem, what do organisms and populations with similar needs compete over?

hram777 [196]

Answer:

In any ecosystem, organisms and populations with similar requirements for food, water, oxygen, or other resources may compete with each other for limited resources, access to which consequently constrains their growth and reproduction. Growth of organisms and population increases are limited by access to resources.

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3 years ago

Which of the following is an example of oxidation? A. Charcoal is placed on a grill and lighting fluid poured over it. B. A car

Vikentia [17]

Answer:

The Answer is (B) A car get rusty over the course of few yearsExplanation:

Explanation:

Oxidation refers to the process of loss of electrons by a molecule,atom or ion during a chemical reaction.The process which is just the opposite of oxidation is reduction,it occurs when their is gain of electrons .
When iron reacts with the oxygen it forms a chemical know as Rust.In this case iron has lost some electrons and the oxygen has gained some electrons

4 0

3 years ago

As discussed in class, the Fischer esterification reactants and products are at equilibrium. How was the equilibrium of the reac

german

Answer:

See explanation

Explanation:

The particular reactants in the Fischer esterification reaction were not stated.

Generally, a Fischer esterification is a reaction that proceeds as follows;

RCOOH + R'OH ⇄RCOOR' + H2O

This reaction occurs in the presence of an acid catalyst.

We can shift the equilibrium of this reaction towards the products side in two ways;

I) use of a large excess of either of the reactants

ii) removal of one of the products as it is formed.

Any of these methods shifts the equilibrium of the Fischer esterification reaction towards the products side.

4 0

3 years ago

Phosphate buffers are commonly used in biological research. If a small amount of strong acid is added to a buffer solution that

lozanna [386]

Answer:

A) [H3PO4] will increase, [KH2PO4] will decrease, and pH will slightly decrease.

Explanation:

A buffer is a solution which resists changes to its pH when a small amount of acid or base is added to it.

Buffers consist of a weak acid (HA) and its conjugate base (A–) or a weak base and its conjugate acid. Weak acids and bases do not completely dissociate in water, and instead exist in solution as an equilibrium of dissociated and undissociated species. When a small quantity of a strong acid is added to a buffer solution, the conjugate base, A-, reacts with the hydrogen ions from the added acid to form the weak acid and a salt thereby removing the extra hydrogen ions from the solution and keeping the pH of the solution fairly constant. On the other hand, if a small quantity of a strong base is added to the buffer solution, the weak acid dissociates further to release hydrogen ions which then react with the hydroxide ions of the added base to form water and the conjugate base.

For example, if a small amount of strong acid is added to a buffer solution that is 0.700 M H3PO4 and 0.700 M KH2PO4, the following reaction is obtained:

KH₂PO₄ + H+ ----> K+ + H₃PO₄

Therefore, [H₃PO₄] will increase, [KH₂PO₄] will decrease, and pH will slightly decrease.:

4 0

3 years ago

Rank the following compounds in order of decreasing boiling point: potassium fluoride (KF), acetylene (C2H2), and formaldehyde (

otez555 [7]

Answer: $KF$ > $CH_2O$ > $C_2H_2$

Explanation:

The order of boiling point depends upon the type of interactions present between the molecules.

Potassium fluoride (KF) is an ionic compound and the opposite ions are held together by strong electrostatic forces.

$C_2H_2$ is a covalent compound and the molecules are held together by weak van der Waals' forces.

Formaldehyde is a polar compound due to presence of polar carbonyl group. Hence dipole-dipole force is present between formaldehyde molecules.

Thus the decreasing order of boiling point is:

$KF$ > $CH_2O$ > $C_2H_2$

8 0

2 years ago