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spin [16.1K]
3 years ago
6

How much momentum, in the x-direction, was transferred to the more massive cart, in kilogram meters per second

Physics
1 answer:
Mars2501 [29]3 years ago
6 0

The momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.

<h3>Momentum transfered to the more massive cart</h3>

The momentum transfered to the more massive cart is determined by applying the principle of conservation of linear momentum as shown below;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

  • m₁ is the mass of the smaller cart
  • u₁ is the initial velocity of the samller cart
  • m₂ is the mass of the bigger cart = 3m₁
  • u₂ is the initial velocity of the bigger cart
  • v₁ is the final velocity of the smaller cart
  • v₂ is the final veocity of the bigger cart

⁻ΔP₁ = ΔP₂

ΔP₂ = m₂v₂ - m₂u₂

ΔP₂ = m₂(v₂ - u₂)

ΔP₂ = 3m₁(v₂ - u₂)

ΔP₂ = 3 x 3.8 x (1.7 - 0)

ΔP₂ = 19.38 kgm/s

Thus, the momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.

The complete question is beblow

A cart of mass 3.8 kg is traveling to the right (which we will take to be the positive x-direction for this problem) at a speed of 6.9 m/s. It collides with a stationary cart that is three times as massive. After the collision, the more massive cart is moving at a speed of 1.7 m/s, to the right.

Learn more about conservation of linear momentum here: brainly.com/question/7538238

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Explanation:

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mλ = dsinθ

when d sin θ = mλ, we expect constructive interference

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5 0
3 years ago
A 0.20 kg mass attached to the end of a spring causes it to stretch 3.0 cm. What is the spring constant? What is the potential e
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Given that the mass is m = 0.2 kg and the displacement is x = 3 cm = 0.03 m

We have to find the spring constant and potential energy.

The spring constant can be calculated by the formula

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Substituting the values, the spring constant will be

\begin{gathered} k=\frac{0.2\times9.8}{0.03} \\ =\text{ 65.33 N/m } \end{gathered}

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Answer:

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Work is a form of energy transferred by an object after the application of a force that act on the object. A step by step explanation is as attached below.

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