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3 years ago

What happens to the open circuit if a small fan is connected at point f and the circuit is closed

1 answer:

4 0

There's no way to tell. Without seeing a diagram of the circuit,
I'll need to know much more about it than you've told me.
I don't know anything about the components or power supply
that are in the circuit, and I don't know where point ' f ' is in it.

Right now, even with the copious volume of all the available
information, no answer to your question is possible.

You might be interested in

A triply charged ion with velocity 7.00 × 10^6 m/s moves in a path of radius 36.0 cm in a magnetic field of 0.55 T in a mass spe

saw5 [17]

Answer:

Mass of ion will be $22\times 10^{-13}kg$

Explanation:

We have given ion is triply charged that is $q=3\times 1.6\times 10^{-19}=4.8\times 10^{-19}C$

Radius r = 36 cm = 0.36 m

Velocity of the electron $v=7\times 10^6m/sec$

Magnetic field B = 0.55 T

We know that radius of the path is given by $r=\frac{mv}{qB}$

$m=\frac{rqB}{v}=\frac{0.36\times 4.8\times 10^{-19}\times 7\times 10^6}{0.55}=22\times 10^{-13}kg$

6 0

3 years ago

A hammer exerts 49.8 N of force on the head (r=0.00510 m) of a nail. How much pressure does it exert on the nail?

Kisachek [45]

Answer:

609547.12 Pa ≈ 6.10×10^5 Pa

Explanation:

Step 1:

Data obtained from the question. This include the following:

Force (F) = 49.8 N

Radius (r) = 0.00510 m

Pressure (P) =..?

Step 2:

Determination of the area of the head of the nail.

The head of a nail is circular in nature. Therefore, the area is given by:

Area (A) = πr²

With the above formula we can obtain the area as follow:

Radius (r) = 0.00510 m

Area (A) =?

A = πr²

A = π x (0.00510)²

A = 8.17×10^-5 m²

Therefore the area of the head of the nail is 8.17×10^-5 m²

Step 3:

Determination of the pressure exerted by the hammer.

This is illustrated below:

Force (F) = 49.8 N

Area (A) = 8.17×10^-5 m²

Pressure (P) =..?

Pressure (P) = Force (F) /Area (A)

P = F/A

P = 49.8/8.17×10^-5

P = 609547.12 N/m²

Now, we shall convert 609547.12 N/m² to Pa.

1 N/m² = 1 Pa

Therefore, 609547.12 N/m² = 609547.12 Pa.

Therefore, the pressure exerted by the hammer on the nail is 609547.12 Pa or 6.10×10^5 Pa

8 0

3 years ago

Why is it important that two different metals are used in building an electrochemic<br> cell?

Mnenie [13.5K]

Answer:

Explanation:

They need a galvanic difference. Or saying that less technically, they need to have different electron attraction, so that one can collect electrons (oxidation/reduction) and flow current from the other. :)

5 0

3 years ago

If the time of impact in a collision is extended by 3 times, by hour much is

vodomira [7]

Answer:

The force of the impact would be smaller

Explanation: Examples:

If the force is big then the time would be small (2500N of Force = 10 seconds)

If the force is small then the time would be big (250N of Force = 50 seconds)

Impulse/Collision -> [Ft] = [M (vf-vo)] <- Change in momentum

4 0

2 years ago

a coil of 40 henry inductance is connected in series with aresistance of 8ohm and the combination is joined to the terminals of

Andreyy89

Answer: 5 seconds

Explanation:

Given the following :

Inductance (L) = 40 henry

Resistance = 8 ohms

The circuit given above is a Resistor - Inductor (RL) circuit network. The time constant of an RL circuit is the ratio of the circuit Inductance (L) and Resistance (R). Time constant is measured in seconds.

THAT IS;

Time constant = L / R

THEREFORE ;

Time constant = 40 / 8

Time constant = 5 seconds

7 0

3 years ago