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a_sh-v [17]
4 years ago
13

What happens to the open circuit if a small fan is connected at point f and the circuit is closed

Physics
1 answer:
liraira [26]4 years ago
4 0
There's no way to tell.  Without seeing a diagram of the circuit,
I'll need to know much more about it than you've told me.
I don't know anything about the components or power supply
that are in the circuit, and I don't know where point ' f ' is in it.

Right now, even with the copious volume of all the available
information, no answer to your question is possible. 
You might be interested in
A force has direction and contact
dalvyx [7]

Answer:

A force has both magnitude and direction, making it a vector quantity. It is measured in the SI unit of newton (N). Force is represented by the symbol F. The original form of Newton's second law states that the net force acting upon an object is equal to the rate at which its momentum changes with time.

Other units: dyne, pound-force, poundal, kip, kilopond

SI unit: newton (N)

Common symbols: F→, F, F

7 0
3 years ago
A 5.0 kg wooden block is placed at an adjustable inclined plane. what is the angle of incline above which the block will start t
Aleks [24]
The value of the angle of the incline \theta at which the block starts to slide is the angle at which the component of the weight parallel to the incline becomes equal to the frictional force that keeps the block on the incline:
mg \sin \theta = \mu N
where the term on the left is the component of the weight parallel to the incline, and the term on the right is the frictional force, which is the product between the coefficient of friction \mu and the normal reaction of the incline N.

The normal reaction of the incline, N, is equal to the component of the weight perpendicular to the incline:
N=mg \cos \theta
Therefore, the initial equation becomes
mg \sin \theta = \mu mg \cos \theta
From which we find
\tan \theta = \mu
\theta = \arctan \mu

For angles above this value, the block will start sliding down, otherwise the block will stay on the incline.

3 0
3 years ago
Help Newton’s laws of motion!!!
Licemer1 [7]
Newton’s 3rd law of motion
6 0
3 years ago
If two firecrackers produce a sound level 85dB. What level does the explosion of one firecracker produce?
mars1129 [50]

Level of sound is related to intensity by this equation

L = 10 Log \frac{I}{I_o}

given that

L = 85 dB

also we know that

I_o = 10^{-12} W/m^2

now we have

85 = 10 Log \frac{I}{10^{-12}}

By solving above equation

I = 10^{8.5} * 10^{-12}

I = 3.16 * 10^{-4} W/m^2

now above is the intensity due to two firecrackers and if we wish to find the sound level of one firecracker then we will find its half level intensity

I_1 = \frac{I}{2}

I_1 = 1.58 * 10^{-4}

now again by above formula

L = 10 Log \frac{1.58 * 10^{-4}}{10^{-12}}

L = 82 dB

8 0
3 years ago
The Pacific Plate is moving 29 mm/year toward the north and 20 mm/year toward the west relative to the North American Plate. Sho
adell [148]

Answer:

7 mm per year

Explanation:

It is given that :

The Pacific plate is moving towards north at = 29 mm per year

The Pacific plate is moving towards west at = 20 mm per year

We have to calculate the total relative motion towards the northwest.

So we have to find the resultant of the two motions.

Since the two movements are perpendicular, therefore the angle between the two motions is 90 degree.

Therefore, finding their resultant,

R^2=(29)^2+(20)^2

R^2=(49)^2

R = 7

Therefore, total relative motion towards the northwest is 7 mm per year.

   

4 0
3 years ago
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